Difference between revisions of "cpp/iterator/next"
(Corrected identifier.) |
(LWG2353, add notes) |
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{{dcl begin}} | {{dcl begin}} | ||
{{dcl header | iterator}} | {{dcl header | iterator}} | ||
− | {{dcl | | + | {{dcl rev multi |
− | template< class | + | | since1=c++11 | dcl1= |
− | + | template< class InputIt > | |
− | + | InputIt next( | |
− | typename std::iterator_traits< | + | InputIt it, |
− | + | typename std::iterator_traits<InputIt>::difference_type n = 1 ); | |
− | + | | since2=c++17 | dcl2= | |
template< class InputIt > | template< class InputIt > | ||
constexpr InputIt next( | constexpr InputIt next( | ||
InputIt it, | InputIt it, | ||
− | typename std::iterator_traits<InputIt>::difference_type n | + | typename std::iterator_traits<InputIt>::difference_type n = 1 ); |
}} | }} | ||
{{dcl end}} | {{dcl end}} | ||
Line 24: | Line 24: | ||
{{par | n | number of elements to advance}} | {{par | n | number of elements to advance}} | ||
{{par hreq}} | {{par hreq}} | ||
− | |||
{{par req named | InputIt | InputIterator}} | {{par req named | InputIt | InputIterator}} | ||
{{par end}} | {{par end}} | ||
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===Possible implementation=== | ===Possible implementation=== | ||
− | {{eq fun | | + | {{eq fun |1= |
− | template<class | + | template<class InputIt> |
− | ForwardIt next( | + | constexpr // since C++17 |
− | typename std::iterator_traits<ForwardIt>::difference_type n | + | ForwardIt next(InputIt it, |
+ | typename std::iterator_traits<ForwardIt>::difference_type n = 1) | ||
{ | { | ||
std::advance(it, n); | std::advance(it, n); | ||
Line 48: | Line 48: | ||
===Notes=== | ===Notes=== | ||
− | Although the expression {{c|++c.begin()}} often compiles, it is not guaranteed to do so: {{c|c.begin()}} is an rvalue expression, and there is no {{named req|BidirectionalIterator}} requirement that specifies that increment of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers, {{c|++c.begin()}} does not compile, while {{c|std::next(c.begin())}} does. | + | Although the expression {{c|++c.begin()}} often compiles, it is not guaranteed to do so: {{c|c.begin()}} is an rvalue expression, and there is no {{named req|BidirectionalIterator}} requirement that specifies that increment of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers or its {{tt|operator++}} is lvalue-ref-qualified, {{c|++c.begin()}} does not compile, while {{c|std::next(c.begin())}} does. |
===Example=== | ===Example=== | ||
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| output=3 4 | | output=3 4 | ||
}} | }} | ||
+ | |||
+ | ===Defect reports=== | ||
+ | {{dr list begin}} | ||
+ | {{dr list item |wg=lwg|dr=2353|std=C++11|before={{tt|next}} required {{named req|ForwardIterator}}|after={{named req|InputIterator}} allowed}} | ||
+ | {{dr list end}} | ||
===See also=== | ===See also=== | ||
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{{dsc end}} | {{dsc end}} | ||
− | + | {{langlinks|de|es|fr|it|ja|pt|ru|zh}} | |
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Revision as of 09:08, 11 July 2020
Defined in header <iterator>
|
||
template< class InputIt > InputIt next( |
(since C++11) (until C++17) |
|
template< class InputIt > constexpr InputIt next( |
(since C++17) | |
Return the nth successor of iterator it.
Contents |
Parameters
it | - | an iterator |
n | - | number of elements to advance |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator.
|
Return value
The nth successor of iterator it.
Complexity
Linear.
However, if InputIt
or ForwardIt
additionally meets the requirements of LegacyRandomAccessIterator, complexity is constant.
Possible implementation
template<class InputIt> constexpr // since C++17 ForwardIt next(InputIt it, typename std::iterator_traits<ForwardIt>::difference_type n = 1) { std::advance(it, n); return it; } |
Notes
Although the expression ++c.begin() often compiles, it is not guaranteed to do so: c.begin() is an rvalue expression, and there is no LegacyBidirectionalIterator requirement that specifies that increment of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers or its operator++
is lvalue-ref-qualified, ++c.begin() does not compile, while std::next(c.begin()) does.
Example
#include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{ 3, 1, 4 }; auto it = v.begin(); auto nx = std::next(it, 2); std::cout << *it << ' ' << *nx << '\n'; }
Output:
3 4
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2353 | C++11 | next required LegacyForwardIterator
|
LegacyInputIterator allowed |
See also
(C++11) |
decrement an iterator (function template) |
advances an iterator by given distance (function template) |