Difference between revisions of "cpp/concepts/common reference with"
From cppreference.com
m (+equality-preserving links) |
D41D8CD98F (Talk | contribs) (- {{cpp/concepts/equality preservation|skip-requires=yes}}) |
||
| Line 16: | Line 16: | ||
In other words, the conversion to the common reference type must [[cpp/concepts#Equality preservation|preserve equality]]. | In other words, the conversion to the common reference type must [[cpp/concepts#Equality preservation|preserve equality]]. | ||
| − | |||
| − | |||
===See also=== | ===See also=== | ||
Revision as of 12:03, 18 June 2023
| Defined in header <concepts>
|
||
| template< class T, class U > concept common_reference_with = |
(since C++20) | |
The concept common_reference_with<T, U> specifies that two types T and U share a common reference type (as computed by std::common_reference_t) to which both can be converted.
Semantic requirements
T and U model std::common_reference_with<T, U> only if, given equality-preserving expressions t1, t2, u1 and u2 such that decltype((t1)) and decltype((t2)) are both T and decltype((u1)) and decltype((u2)) are both U,
- std::common_reference_t<T, U>(t1) equals std::common_reference_t<T, U>(t2) if and only if
t1equalst2; and - std::common_reference_t<T, U>(u1) equals std::common_reference_t<T, U>(u2) if and only if
u1equalsu2.
In other words, the conversion to the common reference type must preserve equality.
See also
| determines the common reference type of a group of types (class template) | |
| (C++20) |
specifies that two types share a common type (concept) |
| (C++11) |
determines the common type of a group of types (class template) |
