Difference between revisions of "cpp/string/byte/memcpy"
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Several C++ compilers transform suitable memory-copying loops to {{tt|std::memcpy}} calls. | Several C++ compilers transform suitable memory-copying loops to {{tt|std::memcpy}} calls. | ||
− | Where | + | Where {{lsd|cpp/language/object#Strict aliasing}} prohibits examining the same memory as values of two different types, {{tt|std::memcpy}} may be used to convert the values. |
===Example=== | ===Example=== | ||
Line 42: | Line 42: | ||
{ | { | ||
// simple usage | // simple usage | ||
− | char source[] = "once upon a | + | char source[] = "once upon a daydream...", dest[4]; |
std::memcpy(dest, source, sizeof dest); | std::memcpy(dest, source, sizeof dest); | ||
− | std::cout << "dest[4] = { "; | + | std::cout << "dest[4] = {"; |
− | for (char c : dest) | + | for (int n{}; char c : dest) |
− | std::cout << '\'' << c << "' | + | std::cout << (n++ ? ", " : "") << '\'' << c << "'"; |
std::cout << "};\n"; | std::cout << "};\n"; | ||
Line 70: | Line 70: | ||
} | } | ||
|output= | |output= | ||
− | dest[4] = { 'o', 'n', 'c', 'e' | + | dest[4] = {'o', 'n', 'c', 'e'}; |
0x1.999999999999ap-4 is 3fb999999999999a as a std::int64_t | 0x1.999999999999ap-4 is 3fb999999999999a as a std::int64_t | ||
{42} | {42} |
Latest revision as of 08:01, 25 October 2023
Defined in header <cstring>
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void* memcpy( void* dest, const void* src, std::size_t count ); |
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Copies count bytes from the object pointed to by src to the object pointed to by dest. Both objects are reinterpreted as arrays of unsigned char.
If the objects overlap, the behavior is undefined.
If either dest or src is an invalid or null pointer, the behavior is undefined, even if count is zero.
If the objects are potentially-overlapping or not TriviallyCopyable, the behavior of memcpy
is not specified and may be undefined.
Contents |
[edit] Parameters
dest | - | pointer to the memory location to copy to |
src | - | pointer to the memory location to copy from |
count | - | number of bytes to copy |
[edit] Return value
dest
[edit] Notes
std::memcpy
may be used to implicitly create objects in the destination buffer.
std::memcpy
is meant to be the fastest library routine for memory-to-memory copy. It is usually more efficient than std::strcpy, which must scan the data it copies or std::memmove, which must take precautions to handle overlapping inputs.
Several C++ compilers transform suitable memory-copying loops to std::memcpy
calls.
Where strict aliasing prohibits examining the same memory as values of two different types, std::memcpy
may be used to convert the values.
[edit] Example
#include <cstdint> #include <cstring> #include <iostream> int main() { // simple usage char source[] = "once upon a daydream...", dest[4]; std::memcpy(dest, source, sizeof dest); std::cout << "dest[4] = {"; for (int n{}; char c : dest) std::cout << (n++ ? ", " : "") << '\'' << c << "'"; std::cout << "};\n"; // reinterpreting double d = 0.1; // std::int64_t n = *reinterpret_cast<std::int64_t*>(&d); // aliasing violation std::int64_t n; std::memcpy(&n, &d, sizeof d); // OK std::cout << std::hexfloat << d << " is " << std::hex << n << " as a std::int64_t\n" << std::dec; // object creation in destination buffer struct S { int x{42}; void print() const { std::cout << '{' << x << "}\n"; } } s; alignas(S) char buf[sizeof(S)]; S* ps = new (buf) S; // placement new std::memcpy(ps, &s, sizeof s); ps->print(); }
Output:
dest[4] = {'o', 'n', 'c', 'e'}; 0x1.999999999999ap-4 is 3fb999999999999a as a std::int64_t {42}
[edit] See also
moves one buffer to another (function) | |
fills a buffer with a character (function) | |
copies a certain amount of wide characters between two non-overlapping arrays (function) | |
copies characters (public member function of std::basic_string<CharT,Traits,Allocator> )
| |
(C++11) |
copies a range of elements to a new location (function template) |
copies a range of elements in backwards order (function template) | |
(C++11) |
checks if a type is trivially copyable (class template) |
C documentation for memcpy
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