Difference between revisions of "cpp/memory/align"
(Undo revision 81684 by 159.153.138.99 (talk) 32 refers to bytes in this example) |
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if (p3) | if (p3) | ||
*p3 = 2; | *p3 = 2; | ||
| − | std::cout << "allocated an int at " << (void*)p3 << " (32 | + | std::cout << "allocated an int at " << (void*)p3 << " (32 byte alignment)\n"; |
} | } | ||
| p = true | | p = true | ||
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allocated a char at 0x2ff21a08 | allocated a char at 0x2ff21a08 | ||
allocated an int at 0x2ff21a0c | allocated an int at 0x2ff21a0c | ||
| − | allocated an int at 0x2ff21a20 (32 | + | allocated an int at 0x2ff21a20 (32 byte alignment) |
}} | }} | ||
Revision as of 14:07, 3 November 2015
| Defined in header <memory>
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| void* align( std::size_t alignment, std::size_t size, |
(since C++11) | |
Given a pointer ptr to a buffer of size space, returns a pointer aligned by the specified alignment for size number of bytes and decreases space argument by the number of bytes used for alignment. The first aligned address is returned.
The function modifies the pointer only if it would be possible to fit the wanted number of bytes aligned by the given alignment into the buffer. If the buffer is too small, the function does nothing and returns nullptr.
The behavior is undefined if alignment is not a fundamental or extended alignment value supported by the implementation(until C++17)power of two(since C++17).
Contents |
Parameters
| alignment | - | the desired alignment |
| size | - | the size of the storage to be aligned |
| ptr | - | pointer to contiguous storage of at least space bytes
|
| space | - | the size of the buffer in which to operate |
Return value
The adjusted value of ptr, or null pointer value if the space provided is too small.
Example
demonstrates the use of std::align to place objects of different type in memory
#include <iostream> #include <memory> template <std::size_t N> struct MyAllocator { char data[N]; void* p; std::size_t sz; MyAllocator() : p(data), sz(N) {} template <typename T> T* aligned_alloc(std::size_t a = alignof(T)) { if (std::align(a, sizeof(T), p, sz)) { T* result = reinterpret_cast<T*>(p); p = (char*)p + sizeof(T); sz -= sizeof(T); return result; } return nullptr; } }; int main() { MyAllocator<64> a; // allocate a char char* p1 = a.aligned_alloc<char>(); if (p1) *p1 = 'a'; std::cout << "allocated a char at " << (void*)p1 << '\n'; // allocate an int int* p2 = a.aligned_alloc<int>(); if (p2) *p2 = 1; std::cout << "allocated an int at " << (void*)p2 << '\n'; // allocate an int, aligned at 32-byte boundary int* p3 = a.aligned_alloc<int>(32); if (p3) *p3 = 2; std::cout << "allocated an int at " << (void*)p3 << " (32 byte alignment)\n"; }
Possible output:
allocated a char at 0x2ff21a08 allocated an int at 0x2ff21a0c allocated an int at 0x2ff21a20 (32 byte alignment)
See also
alignof operator(C++11)
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queries alignment requirements of a type |
alignas specifier(C++11)
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specifies that the storage for the variable should be aligned by specific amount |
| (C++11)(deprecated in C++23) |
defines the type suitable for use as uninitialized storage for types of given size (class template) |
