Namespaces
Variants
Views
Actions

Difference between revisions of "cpp/utility/tuple/make tuple"

From cppreference.com
< cpp‎ | utility‎ | tuple
(code not conform to the text "For each Ti in Types..., the corresponding type Vi in Vtypes... is std::decay<Ti>::type unless application of std::decay results in std::reference_wrapper<X> for some type X, in which case the deduced type is X&.")
(Possible implementation: tweak)
Line 30: Line 30:
 
{{eq fun | 1=
 
{{eq fun | 1=
 
template <class T>
 
template <class T>
struct special_decay
+
struct unwrap_refwrapper
 
{
 
{
 
     using type = T;
 
     using type = T;
Line 36: Line 36:
  
 
template <class T>
 
template <class T>
struct special_decay<std::reference_wrapper<T>>
+
struct unwrap_refwrapper<std::reference_wrapper<T>>
 
{
 
{
 
     using type = T&;
 
     using type = T&;
Line 42: Line 42:
  
 
template <class T>
 
template <class T>
using special_decay_t = typename special_decay<T>::type;
+
using special_decay_t = typename unwrap_refwrapper<typename std::decay<T>::type>::type;
  
 
template <class... Types>
 
template <class... Types>
 
auto make_tuple(Types&&... args)
 
auto make_tuple(Types&&... args)
 
{
 
{
     return std::tuple<special_decay_t<typename std::decay<Types>::type>...>(std::forward<Types>(args)...);
+
     return std::tuple<special_decay_t<Types>...>(std::forward<Types>(args)...);
 
}
 
}
 
}}
 
}}

Revision as of 16:49, 20 February 2016

 
 
Utilities library
General utilities
Relational operators (deprecated in C++20)
 
 
Defined in header <tuple>
template< class... Types >
tuple<VTypes...> make_tuple( Types&&... args );
(since C++11)
(until C++14)
template< class... Types >
constexpr tuple<VTypes...> make_tuple( Types&&... args );
(since C++14)

Creates a tuple object, deducing the target type from the types of arguments.

For each Ti in Types..., the corresponding type Vi in Vtypes... is std::decay<Ti>::type unless application of std::decay results in std::reference_wrapper<X> for some type X, in which case the deduced type is X&.

Contents

Parameters

args - zero or more arguments to construct the tuple from

Return value

A std::tuple object containing the given values, created as if by std::tuple<VTypes...>(std::forward<Types>(t)...).

Possible implementation

template <class T>
struct unwrap_refwrapper
{
    using type = T;
};
 
template <class T>
struct unwrap_refwrapper<std::reference_wrapper<T>>
{
    using type = T&;
};
 
template <class T>
using special_decay_t = typename unwrap_refwrapper<typename std::decay<T>::type>::type;
 
template <class... Types>
auto make_tuple(Types&&... args)
{
    return std::tuple<special_decay_t<Types>...>(std::forward<Types>(args)...);
}

Example

#include <iostream>
#include <tuple>
#include <functional>
 
std::tuple<int, int> f() // this function returns multiple values
{
    int x = 5;
    return std::make_tuple(x, 7); // return {x,7}; in C++17
}
 
int main()
{
    // heterogeneous tuple construction
    int n = 1;
    auto t = std::make_tuple(10, "Test", 3.14, std::ref(n), n);
    n = 7;
    std::cout << "The value of t is "  << "("
              << std::get<0>(t) << ", " << std::get<1>(t) << ", "
              << std::get<2>(t) << ", " << std::get<3>(t) << ", "
              << std::get<4>(t) << ")\n";
 
    // function returning multiple values
    int a, b;
    std::tie(a, b) = f();
    std::cout << a << " " << b << "\n";
}

Output:

The value of t1 is (10, Test, 3.14, 7, 1)
5 7
(C++11)
creates a tuple of lvalue references or unpacks a tuple into individual objects
(function template) [edit]
creates a tuple of forwarding references
(function template) [edit]
(C++11)
creates a tuple by concatenating any number of tuples
(function template) [edit]