Difference between revisions of "cpp/algorithm/equal"

Revision as of 09:00, 21 March 2016

The two ranges are considered equal if, for every iterator i in the range [first1,last1), *i equals *(first2 + (i - first1)). The overloads (1,2,5,6) use operator== to determine if two elements are equal, whereas overloads (3,4,7,8) use the given binary predicate p.

Parameters

Return value

If the elements in the two ranges are equal, returns true.

Otherwise returns false.

Notes

std::equal should not be used to compare the ranges formed by the iterators from std::unordered_set, std::unordered_multiset, std::unordered_map, or std::unordered_multimap because the order in which the elements are stored in those containers may be different even if the two containers store the same elements.

When comparing entire containers for equality, operator== for the corresponding container are usually preferred.

Complexity

Exceptions

The overloads with a template parameter named ExecutionPolicy report errors as follows:

• If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
• If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

template<class InputIt1, class InputIt2>
bool equal(InputIt1 first1, InputIt1 last1, 
           InputIt2 first2)
{
    for (; first1 != last1; ++first1, ++first2) {
        if (!(*first1 == *first2)) {
            return false;
        }
    }
    return true;
}

template<class InputIt1, class InputIt2, class BinaryPredicate>
bool equal(InputIt1 first1, InputIt1 last1, 
           InputIt2 first2, BinaryPredicate p)
{
    for (; first1 != last1; ++first1, ++first2) {
        if (!p(*first1, *first2)) {
            return false;
        }
    }
    return true;
}

Example

#include <algorithm>
#include <iostream>
#include <string>
 
bool is_palindrome(const std::string& s)
{
    return std::equal(s.begin(), s.begin() + s.size()/2, s.rbegin());
}
 
void test(const std::string& s)
{
    std::cout << "\"" << s << "\" "
        << (is_palindrome(s) ? "is" : "is not")
        << " a palindrome\n";
}
 
int main()
{
    test("radar");
    test("hello");
}

"radar" is a palindrome
"hello" is not a palindrome