Difference between revisions of "cpp/regex/regex search"
(how to find all occurrences appears to be a frequently asked question. +note) |
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In order to examine all matches within the target sequence, {{tt|std::regex_search}} may be called in a loop, restarting each time from {{tt|m[0].second}} of the previous call. {{lc|std::regex_iterator}} offers an easy interface to this iteration. | In order to examine all matches within the target sequence, {{tt|std::regex_search}} may be called in a loop, restarting each time from {{tt|m[0].second}} of the previous call. {{lc|std::regex_iterator}} offers an easy interface to this iteration. | ||
− | === | + | ===Examples=== |
{{example | {{example | ||
| code= | | code= | ||
Line 173: | Line 173: | ||
3: ff | 3: ff | ||
matches for 'all of my base are belong to you' | matches for 'all of my base are belong to you' | ||
+ | }} | ||
+ | |||
+ | {{example | ||
+ | | code= | ||
+ | #include <iostream> | ||
+ | #include <regex> | ||
+ | #include <string> | ||
+ | // Parse some log | ||
+ | int main () | ||
+ | { | ||
+ | using namespace std; | ||
+ | string log(R"( | ||
+ | Speed: 366 | ||
+ | Mass: 35 | ||
+ | Speed: 378 | ||
+ | Mass: 32 | ||
+ | Speed: 400 | ||
+ | Mass: 30)"); | ||
+ | regex r(R"(Speed:\t\d*)"); | ||
+ | smatch sm; | ||
+ | while(regex_search(log,sm,r)) | ||
+ | { | ||
+ | cout << sm.str() << endl; | ||
+ | log = sm.suffix().str(); | ||
+ | } | ||
+ | return 0; | ||
+ | } | ||
+ | | output= | ||
+ | Speed: 366 | ||
+ | Speed: 378 | ||
+ | Speed: 400 | ||
}} | }} | ||
Revision as of 14:09, 15 June 2016
Defined in header <regex>
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template< class BidirIt, class Alloc, class CharT, class Traits > |
(1) | (since C++11) |
template< class CharT, class Alloc, class Traits > bool regex_search( const CharT* str, |
(2) | (since C++11) |
template< class STraits, class SAlloc, class Alloc, class CharT, class Traits > |
(3) | (since C++11) |
template< class BidirIt, class CharT, class Traits > |
(4) | (since C++11) |
template< class CharT, class Traits > bool regex_search( const CharT* str, |
(5) | (since C++11) |
template< class STraits, class SAlloc, class CharT, class Traits > |
(6) | (since C++11) |
template< class STraits, class SAlloc, class Alloc, class CharT, class Traits > |
(7) | (since C++14) |
Determines if there is a match between the regular expression e
and some subsequence in the target character sequence.
[first,last)
. Match results are returned in m
.str
. Match results are returned in m
.s
. Match results are returned in m
.regex_search
will successfully match any subsequence of the given sequence, whereas std::regex_match will only return true if the regular expression matches the entire sequence.
Contents |
Parameters
first, last | - | a range identifying the target character sequence |
str | - | a pointer to a null-terminated target character sequence |
s | - | a string identifying target character sequence |
e | - | the std::regex that should be applied to the target character sequence |
m | - | the match results |
flags | - | std::regex_constants::match_flag_type governing search behavior |
Type requirements |
Return value
Returns true if a match exists, false otherwise. In either case, the object m
is updated, as follows:
If the match does not exist:
m.ready() == true | |
m.empty() == true | |
m.size() == 0 |
If the match exists:
m.ready() | true |
m.empty() | false |
m.size() | number of marked subexpressions plus 1, that is, 1+e.mark_count() |
m.prefix().first | first
|
m.prefix().second | m[0].first |
m.prefix().matched | m.prefix().first != m.prefix().second |
m.suffix().first | m[0].second |
m.suffix().second | last
|
m.suffix().matched | m.suffix().first != m.suffix().second |
m[0].first | the start of the matching sequence |
m[0].second | the end of the matching sequence |
m[0].matched | true |
m[n].first | the start of the sequence that matched marked sub-expression n, or last if the subexpression did not participate in the match
|
m[n].second | the end of the sequence that matched marked sub-expression n, or last if the subexpression did not participate in the match
|
m[n].matched | true if sub-expression n participated in the match, false otherwise |
Notes
In order to examine all matches within the target sequence, std::regex_search
may be called in a loop, restarting each time from m[0].second
of the previous call. std::regex_iterator offers an easy interface to this iteration.
Examples
#include <iostream> #include <string> #include <regex> int main() { std::string lines[] = {"Roses are #ff0000", "violets are #0000ff", "all of my base are belong to you"}; std::regex color_regex("#([a-f0-9]{2})" "([a-f0-9]{2})" "([a-f0-9]{2})"); for (const auto &line : lines) { std::cout << line << ": " << std::regex_search(line, color_regex) << '\n'; } std::smatch color_match; for (const auto &line : lines) { std::regex_search(line, color_match, color_regex); std::cout << "matches for '" << line << "'\n"; for (size_t i = 0; i < color_match.size(); ++i) std::cout << i << ": " << color_match[i] << '\n'; } }
Output:
Roses are #ff0000: 1 violets are #0000ff: 1 all of my base are belong to you: 0 matches for 'Roses are #ff0000' 0: #ff0000 1: ff 2: 00 3: 00 matches for 'violets are #0000ff' 0: #0000ff 1: 00 2: 00 3: ff matches for 'all of my base are belong to you'
#include <iostream> #include <regex> #include <string> // Parse some log int main () { using namespace std; string log(R"( Speed: 366 Mass: 35 Speed: 378 Mass: 32 Speed: 400 Mass: 30)"); regex r(R"(Speed:\t\d*)"); smatch sm; while(regex_search(log,sm,r)) { cout << sm.str() << endl; log = sm.suffix().str(); } return 0; }
Output:
Speed: 366 Speed: 378 Speed: 400
See also
(C++11) |
regular expression object (class template) |
(C++11) |
identifies one regular expression match, including all sub-expression matches (class template) |
(C++11) |
attempts to match a regular expression to an entire character sequence (function template) |