std::advance
From cppreference.com
Defined in header <iterator>
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template< class InputIt, class Distance > void advance( InputIt& it, Distance n ); |
(until C++17) | |
template< class InputIt, class Distance > constexpr void advance( InputIt& it, Distance n ); |
(since C++17) | |
Increments given iterator it
by n
elements.
If n
is negative, the iterator is decremented. In this case, InputIt
must meet the requirements of LegacyBidirectionalIterator, otherwise the behavior is undefined.
Contents |
Parameters
it | - | iterator to be advanced |
n | - | number of elements it should be advanced
|
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator.
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Return value
(none)
Complexity
Linear.
However, if InputIt
additionally meets the requirements of LegacyRandomAccessIterator, complexity is constant.
Notes
The behavior is undefined if the specified sequence of increments or decrements would require that a non-incrementable iterator (such as the past-the-end iterator) is incremented, or that a non-decrementable iterator (such as the front iterator or the singular iterator) is decremented.
Possible implementation
See also the implementations in libstdc++ and libc++.
Example
Run this code
#include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{ 3, 1, 4 }; auto vi = v.begin(); std::advance(vi, 2); std::cout << *vi << '\n'; }
Output:
4
See also
(C++11) |
increment an iterator (function template) |
returns the distance between two iterators (function template) |