std::real(std::complex)
From cppreference.com
Defined in header <complex>
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(1) | ||
template< class T > T real( const std::complex<T>& z ); |
(until C++14) | |
template< class T > constexpr T real( const std::complex<T>& z ); |
(since C++14) | |
(2) | ||
float real( float f ); double real( double f ); |
(since C++11) (until C++14) |
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constexpr float real( float f ); constexpr double real( double f ); |
(since C++14) (until C++23) |
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template< class FloatingPoint > constexpr FloatingPoint real( FloatingPoint f ); |
(since C++23) | |
(3) | ||
template< class Integer > double real( Integer i ); |
(since C++11) (until C++14) |
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template< class Integer > constexpr double real( Integer i ); |
(since C++14) | |
1) Returns the real part of the complex number z, i.e. z.real().
2,3) Additional overloads are provided for all integer and floating-point types, which are treated as complex numbers with zero imaginary part.
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(since C++11) |
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Parameters
z | - | complex value |
f | - | floating-point value |
i | - | integer value |
Return value
1) The real part of z.
2) f.
3) static_cast<double>(i).
Notes
The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:
- If num has a standard(until C++23) floating-point type
T
, then std::real(num) has the same effect as std::real(std::complex<T>(num)). - Otherwise, if num has an integer type, then std::real(num) has the same effect as std::real(std::complex<double>(num)).
See also
accesses the real part of the complex number (public member function) | |
returns the imaginary part (function template) | |
C documentation for creal
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