deduction guides for std::{{{1}}}
From cppreference.com
Revision as of 01:57, 28 June 2023 by D41D8CD98F (Talk | contribs)
|
||
template< class InputIt, class Alloc = std::allocator<typename std::iterator_traits<InputIt>::value_type>> |
(1) | (since C++17) |
template< ranges::input_range R, class Alloc = std::allocator<ranges::range_value_t<R>> > |
(2) | (since C++23) |
1) This deduction guide is provided for {{{1}}} to allow deduction from an iterator range. This overload participates in overload resolution only if
InputIt
satisfies LegacyInputIterator and Alloc
satisfies Allocator.2) This deduction guide is provided for {{{1}}} to allow deduction from a std::from_range_t tag and an
input_range
.Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type
must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.
Example
Run this code
#include <{{{1}}}> #include <vector> int main() { std::vector<int> v = {1, 2, 3, 4}; // uses explicit deduction guide to deduce std::{{{1}}}<int> std::{{{1}}} x(v.begin(), v.end()); // deduces std::{{{1}}}<std::vector<int>::iterator> // first phase of overload resolution for list-initialization selects the candidate // synthesized from the initializer-list constructor; second phase is not performed and // deduction guide has no effect std::{{{1}}} y{v.begin(), v.end()}; }