std::type_info::hash_code

 

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type_info type_index (C++11)	bad_typeid bad_cast

 

std::type_info

Member functions

type_info::~type_info

type_info::operator==type_info::operator!= (until C++20)

type_info::before

type_info::hash_code (C++11)

type_info::name

 

std::size_t hash_code() const noexcept;		(since C++11)

Returns an unspecified value (here denoted by hash code) such that for all std::type_info objects referring to the same type, their hash code is the same.

No other guarantees are given: std::type_info objects referring to different types may have the same hash code (although the standard recommends that implementations avoid this as much as possible), and hash code for the same type can change between invocations of the same program.

Parameters

(none)

Return value

A value that is identical for all std::type_info objects referring to the same type.

Example

The following program is an example of an efficient type-value mapping without using std::type_index.

Run this code

#include <functional>
#include <iostream>
#include <memory>
#include <string>
#include <typeinfo>
#include <unordered_map>
 
struct A
{
    virtual ~A() {}
};
 
struct B : A {};
struct C : A {};
 
using TypeInfoRef = std::reference_wrapper<const std::type_info>;
 
struct Hasher
{
    std::size_t operator()(TypeInfoRef code) const
    {
        return code.get().hash_code();
    }
};
 
struct EqualTo
{
    bool operator()(TypeInfoRef lhs, TypeInfoRef rhs) const
    {
        return lhs.get() == rhs.get();
    }
};
 
int main()
{
    std::unordered_map<TypeInfoRef, std::string, Hasher, EqualTo> type_names;
 
    type_names[typeid(int)] = "int";
    type_names[typeid(double)] = "double";
    type_names[typeid(A)] = "A";
    type_names[typeid(B)] = "B";
    type_names[typeid(C)] = "C";
 
    int i;
    double d;
    A a;
 
    // note that we're storing pointer to type A
    std::unique_ptr<A> b(new B);
    std::unique_ptr<A> c(new C);
 
    std::cout << "i is " << type_names[typeid(i)] << '\n';
    std::cout << "d is " << type_names[typeid(d)] << '\n';
    std::cout << "a is " << type_names[typeid(a)] << '\n';
    std::cout << "*b is " << type_names[typeid(*b)] << '\n';
    std::cout << "*c is " << type_names[typeid(*c)] << '\n';
}

Output:

i is int
d is double
a is A
*b is B
*c is C

See also

operator==operator!= (removed in C++20)	checks whether the objects refer to the same type (public member function)
name	implementation defined name of the type (public member function)