std::type_identity
From cppreference.com
| Defined in header <type_traits>
|
||
| template< class T > struct type_identity; |
(since C++20) | |
Provides the member typedef type that names T (i.e., the identity transformation).
If the program adds specializations for std::type_identity, the behavior is undefined.
Contents |
[edit] Member types
| Name | Definition |
type
|
T
|
[edit] Helper types
| template< class T > using type_identity_t = type_identity<T>::type; |
(since C++20) | |
[edit] Possible implementation
template<class T> struct type_identity { using type = T; }; |
[edit] Notes
std::type_identity can be used to establish non-deduced contexts in template argument deduction.
| Feature-test macro | Value | Std | Feature |
|---|---|---|---|
__cpp_lib_type_identity |
201806L | (C++20) | std::type_identity
|
[edit] Example
Run this code
#include <iostream> #include <type_traits> template<class T> T foo(T a, T b) { return a + b; } template<class T> T bar(T a, std::type_identity_t<T> b) { return a + b; } int main() { // foo(4.2, 1); // error, deduced conflicting types for 'T' std::cout << bar(4.2, 1) << '\n'; // OK, calls bar<double> }
Output:
5.2
[edit] See also
| (C++20) |
function object that returns its argument unchanged (class) |
