std::tuple<Types...>::operator=
From cppreference.com
tuple& operator=( const tuple& other ); |
(1) | (since C++11) (constexpr since C++20) |
constexpr const tuple& operator=( const tuple& other ) const; |
(2) | (since C++23) |
tuple& operator=( tuple&& other ) noexcept(/* see below */); |
(3) | (since C++11) (constexpr since C++20) |
constexpr const tuple& operator=( tuple&& other ) const; |
(4) | (since C++23) |
template< class... UTypes > tuple& operator=( const tuple<UTypes...>& other ); |
(5) | (since C++11) (constexpr since C++20) |
template< class... UTypes > constexpr const tuple& operator=( const tuple<UTypes...>& other ) const; |
(6) | (since C++23) |
template< class... UTypes > tuple& operator=( tuple<UTypes...>&& other ); |
(7) | (since C++11) (constexpr since C++20) |
template< class... UTypes > constexpr const tuple& operator=( tuple<UTypes...>&& other ) const; |
(8) | (since C++23) |
template< class E1, class E2 > tuple& operator=( const std::pair<E1, E2>& p ); |
(9) | (since C++11) (constexpr since C++20) |
template< class E1, class E2 > constexpr const tuple& operator=( const std::pair<E1, E2>& p ) const; |
(10) | (since C++23) |
template< class E1, class E2 > tuple& operator=( std::pair<E1, E2>&& p ); |
(11) | (since C++11) (constexpr since C++20) |
template< class E1, class E2 > constexpr const tuple& operator=( std::pair<E1, E2>&& p ) const; |
(12) | (since C++23) |
template< tuple-like UTuple > constexpr tuple& operator=( UTuple&& u ); |
(13) | (since C++23) |
template< tuple-like UTuple > constexpr const tuple& operator=( UTuple&& u ) const; |
(14) | (since C++23) |
Replaces the contents of the tuple with the contents of another tuple-like object.
In the descriptions that follow, let
- i be in the range
[
0,
sizeof...(Types))
in order, -
Ti
be thei
th type in the class template parameter packTypes
, and -
Ui
be thei
th type in a function template parameter pack namedUTypes
,
where indexing is zero-based.
1) Copy assignment operator. Assigns each element of other to the corresponding element of *this.
2) Copy assignment operator for const-qualified operand. Assigns each element of other to the corresponding element of *this.
This overload participates in overload resolution only if std::is_copy_assignable_v<const Ti> is true for all
Ti
.3) Move assignment operator. For all i, assigns std::forward<Ti>(std::get<i>(other)) to std::get<i>(*this).
This overload participates in overload resolution only if std::is_move_assignable<Ti>::value is true for all
Ti
.4) Move assignment operator for const-qualified operand. For all i, assigns std::forward<Ti>(std::get<i>(other)) to std::get<i>(*this).
This overload participates in overload resolution only if std::is_assignable_v<const Ti&, Ti> is true for all
Ti
.5) For all i, assigns std::get<i>(other) to std::get<i>(*this).
This overload participates in overload resolution only if sizeof...(Types) == sizeof...(UTypes), and std::is_assignable<Ti&, const Ui&>::value is true for all corresponding pairs of types
Ti
and Ui
.6) For all i, assigns std::get<i>(other) to std::get<i>(*this).
This overload participates in overload resolution only if sizeof...(Types) == sizeof...(UTypes), and std::is_assignable_v<const Ti&, const Ui&> is true for all corresponding pairs of types
Ti
and Ui
. This overload participates in overload resolution only if sizeof...(Types) == sizeof...(UTypes), and std::is_assignable<Ti&, Ui>::value is true for all corresponding pairs of types
Ti
and Ui
. This overload participates in overload resolution only if sizeof...(Types) == sizeof...(UTypes), and std::is_assignable_v<const Ti&, Ui> is true for all corresponding pairs of types
Ti
and Ui
.9) Assigns p.first to the first element of *this and p.second to the second element of *this.
This overload participates in overload resolution only if
- sizeof...(Types) == 2,
- std::is_assignable<T0&, const E1&>::value is true, and
- std::is_assignable<T1&, const E2&>::value is true.
10) Assigns p.first to the first element and p.second to the second element.
This overload participates in overload resolution only if
- sizeof...(Types) == 2,
- std::is_assignable_v<const T0&, const E1&> is true, and
- std::is_assignable_v<const T1&, const E2&> is true.
11) Assigns std::forward<E1>(p.first) to the first element of *this and std::forward<E2>(p.second) to the second element of *this.
This overload participates in overload resolution only if
- sizeof...(Types) == 2,
- std::is_assignable_v<T0&, E1> is true, and
- std::is_assignable_v<T1&, E2> is true.
12) Assigns std::forward<E1>(p.first) to the first element and std::forward<E2>(p.second) to the second element.
This overload participates in overload resolution only if
- sizeof...(Types) == 2,
- std::is_assignable_v<const T0&, E1> is true, and
- std::is_assignable_v<const T1&, E2> is true.
This overload participates in overload resolution only if
- std::same_as<std::remove_cvref_t<UTuple>, std::tuple> is false,
- std::remove_cvref_t<UTuple> is not a specialization of std::ranges::subrange,
- sizeof...(Types) equals std::tuple_size_v<std::remove_cvref_t<UTuple>>, and
- std::is_assignable_v<Ti&, decltype(std::get<i>(std::forward<UTuple>(u)))> is true for all i.
This overload participates in overload resolution only if
- std::same_as<std::remove_cvref_t<UTuple>, std::tuple> is false,
- std::remove_cvref_t<UTuple> is not a specialization of std::ranges::subrange,
- sizeof...(Types) equals std::tuple_size_v<std::remove_cvref_t<UTuple>>, and
- std::is_assignable_v<const Ti&, decltype(std::get<i>(std::forward<UTuple>(u)))> is true for all i.
Contents |
Parameters
other | - | tuple to replace the contents of this tuple |
p | - | pair to replace the contents of this 2-tuple |
u | - | tuple-like object to replace the contents of this tuple
|
Return value
*this
Exceptions
1,2) May throw implementation-defined exceptionsif the assignment of one of the types in
Types
throws an exception.3)
noexcept specification:
noexcept(
std::is_nothrow_move_assignable<T0>::value &&
std::is_nothrow_move_assignable<T1>::value &&
std::is_nothrow_move_assignable<T2>::value &&
...
4-14) May throw implementation-defined exceptionsif the assignment of one of the types in
Types
throws an exception.Example
Run this code
#include <iostream> #include <string> #include <string_view> #include <tuple> #include <utility> #include <vector> // helper function to print std::vector<int> std::ostream& operator<<(std::ostream& os, std::vector<int> const& v) { os << '{'; for (std::size_t t = 0; t != v.size(); ++t) os << v[t] << (t + 1 < v.size() ? ", " : ""); return os << '}'; } // helpers to print a tuple of any size template<class... Args> void print_tuple(std::string_view name, const std::tuple<Args...>& t) { std::cout << name << " = {"; std::apply([&](auto&& arg, auto&&... args) { std::cout << arg; ((std::cout << ", " << args), ...); }, t); std::cout << '}'; } template<class Tuple1, class Tuple2> void print_tuples(std::string_view name1, const Tuple1& t1, std::string_view name2, const Tuple2& t2) { print_tuple(name1, t1); std::cout << ", "; print_tuple(name2, std::tuple(t2)); std::cout << "\n\n"; } int main() { // Tuple to tuple examples // std::tuple<int, std::string, std::vector<int>> t1{1, "alpha", {1, 2, 3}}, t2{2, "beta", {4, 5}}; print_tuples("1) t1", t1, "t2", t2); // Normal copy assignment // operator=( const tuple& other ); t1 = t2; print_tuples("2) t1 = t2;\n t1", t1, "t2", t2); // Normal move assignment // operator=( tuple&& other ); t1 = std::move(t2); print_tuples("3) t1 = std::move(t2);\n t1", t1, "t2", t2); // Converting copy assignment // operator=( const tuple<UTypes...>& other ); std::tuple<short, const char*, std::vector<int>> t3{3, "gamma", {6, 7, 8}}; t1 = t3; print_tuples("4) t1 = t3;\n t1", t1, "t3", t3); // Converting move assignment // operator=( tuple<UTypes...>&& other ); t1 = std::move(t3); print_tuples("5) t1 = std::move(t3);\n t1", t1, "t3", t3); // Pair to tuple examples // std::tuple<std::string, std::vector<int>> t4{"delta", {10, 11, 12}}; std::pair<const char*, std::vector<int>> p1{"epsilon", {14, 15, 16}}; print_tuples("6) t4", t4, "p1", p1); // Converting copy assignment from std::pair // operator=( const std::pair<U1, U2>& p ); t4 = p1; print_tuples("7) t4 = p1;\n t4", t4, "p1", p1); // Converting move assignment from std::pair // operator=( std::pair<U1, U2>&& p ); t4 = std::move(p1); print_tuples("8) t4 = std::move(p1);\n t4", t4, "p1", p1); }
Possible output:
1) t1 = {1, alpha, {1, 2, 3}}, t2 = {2, beta, {4, 5}} 2) t1 = t2; t1 = {2, beta, {4, 5}}, t2 = {2, beta, {4, 5}} 3) t1 = std::move(t2); t1 = {2, beta, {4, 5}}, t2 = {2, , {}} 4) t1 = t3; t1 = {3, gamma, {6, 7, 8}}, t3 = {3, gamma, {6, 7, 8}} 5) t1 = std::move(t3); t1 = {3, gamma, {6, 7, 8}}, t3 = {3, gamma, {}} 6) t4 = {delta, {10, 11, 12}}, p1 = {epsilon, {14, 15, 16}} 7) t4 = p1; t4 = {epsilon, {14, 15, 16}}, p1 = {epsilon, {14, 15, 16}} 8) t4 = std::move(p1); t4 = {epsilon, {14, 15, 16}}, p1 = {epsilon, {}}
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2729 | C++11 | operator= was unconstrained and might result in unnecessary undefined behavior |
constrained |
See also
constructs a new tuple (public member function) | |
assigns the contents (public member function of std::pair<T1,T2> )
|