assert
Defined in header <cassert>
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Disabled assertion |
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(1) | ||
#define assert(condition) ((void)0) |
(until C++26) | |
#define assert(...) ((void)0) |
(since C++26) | |
Enabled assertion |
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(2) | ||
#define assert(condition) /* unspecified */ |
(until C++26) | |
#define assert(...) /* unspecified */ |
(since C++26) | |
The definition of the macro assert
depends on another macro, NDEBUG, which is not defined by the standard library.
assert
does nothing.
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(until C++26) |
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(since C++26) |
The expression assert(E) is guaranteed to be a constant subexpression, if either
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(since C++17) |
Contents |
[edit] Parameters
condition | - | expression of scalar type |
[edit] Return value
(none)
[edit] Notes
Because assert(std::is_same_v<int, int>); // error: assert does not take two arguments assert((std::is_same_v<int, int>)); // OK: one argument static_assert(std::is_same_v<int, int>); // OK: not a macro std::complex<double> c; assert(c == std::complex<double>{0, 0}); // error assert((c == std::complex<double>{0, 0})); // OK |
(until C++26) |
There is no standardized interface to add an additional message to assert
errors. A portable way to include one is to use a comma operator provided it has not been overloaded, or use &&
with a string literal:
assert(("There are five lights", 2 + 2 == 5)); assert(2 + 2 == 5 && "There are five lights");
The implementation of assert
in Microsoft CRT does not conform to C++11 and later revisions, because its underlying function (_wassert
) takes neither __func__ nor an equivalent replacement.
Even though the change of assert
in C23/C++26 is not formally a defect report, the C committee recommends implementations to backport the change to old modes.
[edit] Example
#include <iostream> // uncomment to disable assert() // #define NDEBUG #include <cassert> // Use (void) to silence unused warnings. #define assertm(exp, msg) assert(((void)msg, exp)) int main() { assert(2 + 2 == 4); std::cout << "Checkpoint #1\n"; assert((void("void helps to avoid 'unused value' warning"), 2 * 2 == 4)); std::cout << "Checkpoint #2\n"; assert((010 + 010 == 16) && "Yet another way to add an assert message"); std::cout << "Checkpoint #3\n"; assertm((2 + 2) % 3 == 1, "Success"); std::cout << "Checkpoint #4\n"; assertm(2 + 2 == 5, "Failed"); // assertion fails std::cout << "Execution continues past the last assert\n"; // No output }
Possible output:
Checkpoint #1 Checkpoint #2 Checkpoint #3 Checkpoint #4 main.cpp:23: int main(): Assertion `((void)"Failed", 2 + 2 == 5)' failed. Aborted
[edit] See also
static_assert declaration (C++11)
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performs compile-time assertion checking |
causes abnormal program termination (without cleaning up) (function) | |
C documentation for assert
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