std::extent
From cppreference.com
Defined in header <type_traits>
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template< class T, unsigned N = 0 > struct extent; |
(since C++11) | |
If T
is an array type, provides the member constant value
equal to the number of elements along the N
th dimension of the array, if N
is in [
0,
std::rank<T>::value)
. For any other type, or if T
is an array of unknown bound along its first dimension and N
is 0, value
is 0.
If the program adds specializations for std::extent
or std::extent_v
(since C++17), the behavior is undefined.
Contents |
[edit] Helper variable template
template< class T, unsigned N = 0 > constexpr std::size_t extent_v = extent<T, N>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
the number of elements along the N th dimension of T (public static member constant) |
Member functions
operator std::size_t |
converts the object to std::size_t, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
std::size_t |
type
|
std::integral_constant<std::size_t, value> |
[edit] Possible implementation
template<class T, unsigned N = 0> struct extent : std::integral_constant<std::size_t, 0> {}; template<class T> struct extent<T[], 0> : std::integral_constant<std::size_t, 0> {}; template<class T, unsigned N> struct extent<T[], N> : std::extent<T, N - 1> {}; template<class T, std::size_t I> struct extent<T[I], 0> : std::integral_constant<std::size_t, I> {}; template<class T, std::size_t I, unsigned N> struct extent<T[I], N> : std::extent<T, N - 1> {}; |
[edit] Example
Run this code
#include <type_traits> static_assert( std::extent_v<int[3]> == 3 && // default dimension is 0 std::extent_v<int[3], 0> == 3 && // the same as above std::extent_v<int[3][4], 0> == 3 && std::extent_v<int[3][4], 1> == 4 && std::extent_v<int[3][4], 2> == 0 && std::extent_v<int[]> == 0 ); int main() { const auto ext = std::extent<int['*']>{}; static_assert(ext == 42); // with implicit conversion to std::size_t const int ints[]{1, 2, 3, 4}; static_assert(std::extent_v<decltype(ints)> == 4); // array size [[maybe_unused]] int ary[][3] = {{1, 2, 3}}; // ary[0] is of type reference to 'int[3]', so, the extent // cannot be calculated correctly and it returns 0 static_assert(std::is_same_v<decltype(ary[0]), int(&)[3]>); static_assert(std::extent_v<decltype(ary[0])> == 0); // removing reference gives correct extent value 3 static_assert(std::extent_v<std::remove_cvref_t<decltype(ary[0])>> == 3); }
[edit] See also
(C++11) |
checks if a type is an array type (class template) |
(C++11) |
obtains the number of dimensions of an array type (class template) |
(C++11) |
removes one extent from the given array type (class template) |
(C++11) |
removes all extents from the given array type (class template) |
(C++23) |
a descriptor of a multidimensional index space of some rank (class template) |