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std::search

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Revision as of 17:58, 2 July 2013 by Jogojapan (Talk | contribs)

 
 
Algorithm library
Constrained algorithms and algorithms on ranges (C++20)
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(C++17)
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(C++11)                (C++11)(C++11)

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(C++11)
(C++11)
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(until C++17)(C++11)
(C++20)(C++20)
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(C++17)

Sorting and related operations
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(C++17)
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C library
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Defined in header <algorithm>
template< class ForwardIt1, class ForwardIt2 >

ForwardIt1 search( ForwardIt1 first, ForwardIt1 last,

                   ForwardIt2 s_first, ForwardIt2 s_last );
(1)
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate >

ForwardIt1 search( ForwardIt1 first, ForwardIt1 last,

                   ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p );
(2)

Searches for the first occurrence of the subsequence of elements [s_first, s_last) in the range [first, last - (s_last - s_first)). The first version uses operator== to compare the elements, the second version uses the given binary predicate p.

Contents

Parameters

first, last - the range of elements to examine
s_first, s_last - the range of elements to search for
p - binary predicate which returns ​true if the elements should be treated as equal.

The signature of the predicate function should be equivalent to the following:

 bool pred(const Type1 &a, const Type2 &b);

While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that objects of types ForwardIt1 and ForwardIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

Type requirements

Template:par req concept

Return value

Iterator to the beginning of first subsequence [s_first, s_last) in the range [first, last - (s_last - s_first)). If no such subsequence is found, last is returned.
If [s_first, s_last) is empty, first is returned. (since C++11)

Complexity

At most S*N comparisons where S = std::distance(s_first, s_last) and N = std::distance(first, last).

Possible implementation

First version
template<class ForwardIt1, class ForwardIt2>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
                        ForwardIt2 s_first, ForwardIt2 s_last)
{
    for (; ; ++first) {
        ForwardIt1 it = first;
        for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
            if (s_it == s_last) {
                return first;
            }
            if (it == last) {
                return last;
            }
            if (!(*it == *s_it)) {
                break;
            }
        }
    }
}
Second version
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
                        ForwardIt2 s_first, ForwardIt2 s_last, 
                        BinaryPredicate p)
{
    for (; ; ++first) {
        ForwardIt1 it = first;
        for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
            if (s_it == s_last) {
                return first;
            }
            if (it == last) {
                return last;
            }
            if (!p(*it, *s_it)) {
                break;
            }
        }
    }
}

Example

#include <string>
#include <algorithm>
#include <iostream>
 
template<typename Container>
bool in_quote(const Container& cont, const std::string& s)
{
    return std::search(cont.begin(), cont.end(), s.begin(), s.end()) != cont.end();
}
 
int main()
{
    std::string str = "why waste time learning, when ignorance is instantaneous?";
    // str.find() can be used as well
    std::cout << std::boolalpha << in_quote(str, "learning") << '\n'
                                << in_quote(str, "lemming")  << '\n';
 
    std::vector<char> vec(str.begin(), str.end());
    std::cout << std::boolalpha << in_quote(vec, "learning") << '\n'
                                << in_quote(vec, "lemming")  << '\n';
}

Output:

true
false
true
false

See also

finds the last sequence of elements in a certain range
(function template) [edit]
determines if two sets of elements are the same
(function template) [edit]
finds the first element satisfying specific criteria
(function template) [edit]
returns true if one range is lexicographically less than another
(function template) [edit]
finds the first position where two ranges differ
(function template) [edit]
searches for the first occurrence of a number consecutive copies of an element in a range
(function template) [edit]