constexpr specifier (since C++11)
From cppreference.com
constexpr
- specifies that the value of a variable or function can appear in constant expressions
Explanation
The constexpr
specifier declares that it is possible to evaluate the value of the function or variable at compile time. Such variables and functions can then be used where only compile time constant expressions are allowed.A constexpr specifier used in an object declaration implies const.
A constexpr variable must satisfy the following requirements:
- it must be immediately constructed or assigned a value.
- the constructor parameters or the value to be assigned must contain only literal values,
constexpr
variables and functions. - the constructor used to construct the object (either implicit or explicit) must satisfy the requirements of
constexpr
constructor. In the case of explicit constructor, it must have constexpr specified.
A constexpr function must satisfy the following requirements:
- it must not be virtual
- its return type must be Template:concept
- each of its parameters must be literal type
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(until C++14) |
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(since C++14) |
A constexpr constructor must satisfy the following requirements:
- each of its parameters must be literal type
- the class must have no virtual base classes
- the constructor body must be either deleted or defaulted or contain only the following:
- null statements
- static_assert declarations
- typedef declarations and alias declarations that do not define classes or enumerations
- using declarations
- using directives
- the constructor must not have a function-try block
- every base class and every non-static member must be initialized, either in the constructors initialization list or by a member brace-or-equal initializer. In addition, every constructor involved must be a constexpr constructor and every clause of every brace-or-equal initializer must be a constant expression
- every implicit conversion involved must be a constant expression
This section is incomplete Reason: c++14 |
Keywords
Example
Definition of a constexpr function which computes factorials and a literal type that extends string literals:
Run this code
#include <iostream> #include <stdexcept> // constexpr functions use recursion rather than iteration constexpr int factorial(int n) { return n <= 1 ? 1 : (n * factorial(n-1)); } // literal class class conststr { const char * p; std::size_t sz; public: template<std::size_t N> constexpr conststr(const char(&a)[N]) : p(a), sz(N-1) {} // constexpr functions signal errors by throwing exceptions from operator ?: constexpr char operator[](std::size_t n) const { return n < sz ? p[n] : throw std::out_of_range(""); } constexpr std::size_t size() const { return sz; } }; constexpr std::size_t countlower(conststr s, std::size_t n = 0, std::size_t c = 0) { return n == s.size() ? c : s[n] >= 'a' && s[n] <= 'z' ? countlower(s, n+1, c+1) : countlower(s, n+1, c); } // output function that requires a compile-time constant, for testing template<int n> struct constN { constN() { std::cout << n << '\n'; } }; int main() { std::cout << "4! = " ; constN<factorial(4)> out1; // computed at compile time volatile int k = 8; // disallow optimization using volatile std::cout << k << "! = " << factorial(k) << '\n'; // computed at run time std::cout << "Number of lowercase letters in \"Hello, world!\" is "; constN<countlower("Hello, world!")> out2; // implicitly converted to conststr }
Output:
4! = 24 8! = 40320 Number of lowercase letters in "Hello, world!" is 9