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noexcept operator (since C++11)

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Revision as of 05:36, 10 April 2014 by 60.55.10.131 (Talk)

 
 
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    noexcept specification (C++11)
    dynamic specification (until C++17*)
noexcept operator (C++11)
 

The noexcept operator performs a compile-time check that returns true if an expression is declared to not throw any exceptions.

It can be used within a function template's noexcept specifier to declare that the function will throw exceptions for some types but not others.

Contents

Syntax

noexcept( expression )

Returns a prvalue of type bool.

Explanation

The noexcept operator does not evaluate expression. The result is false if the expression contains at least one of the following potentially evaluated constructs:

In all other cases the result is true.

Keywords

noexcept

Example

#include <iostream>
#include <utility>
 
void may_throw();
void no_throw() noexcept;
auto lmay_throw = []{};
auto lno_throw = []() noexcept {};
class T{
public:
  ~T(){}
};
int main()
{
 
 
  std::cout << std::boolalpha
            << "Is may_throw() noexcept? " << noexcept(may_throw()) << '\n'
            << "Is no_throw() noexcept? " << noexcept(no_throw()) << '\n'
            << "Is lmay_throw() noexcept? " << noexcept(lmay_throw()) << '\n'
            << "Is lno_throw() noexcept? " << noexcept(lno_throw()) << '\n'
            << "Is ~T() noexcept? " << noexcept(std::declval<T>().~T()) << '\n';
 
 
 
 
}

See also

noexcept specifier(C++11) specifies whether a function could throw exceptions[edit]
Dynamic exception specification(until C++17) specifies what exceptions are thrown by a function (deprecated in C++11) [edit]