noexcept operator (since C++11)
From cppreference.com
The noexcept
operator performs a compile-time check that returns true if an expression is declared to not throw any exceptions.
It can be used within a function template's noexcept specifier to declare that the function will throw exceptions for some types but not others.
Contents |
Syntax
noexcept( expression )
|
|||||||||
Returns a prvalue of type bool.
Explanation
The noexcept
operator does not evaluate expression. The result is false
if the expression contains at least one of the following potentially evaluated constructs:
- call to any type of function that does not have non-throwing exception specification, unless it is a constant expression.
-
throw
expression. -
dynamic_cast
expression when the target type is a reference type, and conversion needs a run time check -
typeid
expression when argument type is polymorphic class type
In all other cases the result is true
.
Keywords
Example
Run this code
#include <iostream> #include <utility> void may_throw(); void no_throw() noexcept; auto lmay_throw = []{}; auto lno_throw = []() noexcept {}; class T{ public: ~T(){} }; int main() { std::cout << std::boolalpha << "Is may_throw() noexcept? " << noexcept(may_throw()) << '\n' << "Is no_throw() noexcept? " << noexcept(no_throw()) << '\n' << "Is lmay_throw() noexcept? " << noexcept(lmay_throw()) << '\n' << "Is lno_throw() noexcept? " << noexcept(lno_throw()) << '\n' << "Is ~T() noexcept? " << noexcept(std::declval<T>().~T()) << '\n'; }
See also
noexcept specifier(C++11)
|
specifies whether a function could throw exceptions |
Dynamic exception specification(until C++17) | specifies what exceptions are thrown by a function (deprecated in C++11) |