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std::conjunction

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Revision as of 22:23, 16 November 2016 by T. Canens (Talk | contribs)

 
 
Utilities library
General utilities
Relational operators (deprecated in C++20)
 
 
Defined in header <type_traits>
template<class... B>
struct conjunction;
(1) (since C++17)

Forms the logical conjunction of the type traits B..., effectively performing a logical AND on the sequence of traits.

The specialization std::conjunction<B1, ..., BN> has a public and unambiguous base that is

  • if sizeof...(B) == 0, std::true_type; otherwise
  • the first type Bi in B1, ..., BN for which bool(Bi::value) == false, or BN if there is no such type.

The member names of the base class, other than conjunction and operator=, are not hidden and are unambiguously available in conjunction.

Conjunction is short-circuiting: if there is a template type argument Bi with bool(Bi::value) == false, then instantiating conjunction<B1, ..., BN>::value does not require the instantiation of Bj::value for j > i

Contents

Template parameters

B... - every template argument Bi for which Bi::value is instantiated must be usable as a base class and define member value that is convertible to bool

Helper variable template

template<class... B>
constexpr bool conjunction_v = conjunction<B...>::value;
(since C++17)

Possible implementation

template<class...> struct conjunction : std::true_type { };
template<class B1> struct conjunction<B1> : B1 { };
template<class B1, class... Bn>
struct conjunction<B1, Bn...> 
    : std::conditional_t<bool(B1::value), conjunction<Bn...>, B1> {};

Notes

A specialization of conjunction does not necessarily inherit from either std::true_type or std::false_type: it simply inherits from the first B whose ::value, explicitly converted to bool, is false, or the base characteristic of the very last B when all of them convert to true. For example, std::conjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value is 4.

Example

#include <iostream>
#include <type_traits>
 
// func is enabled if all Ts... have the same type as T
template<typename T, typename... Ts>
std::enable_if_t<std::conjunction_v<std::is_same<T, Ts>...>>
func(T, Ts...) {
    std::cout << "all types in pack are T\n";
}
 
// otherwise
template<typename T, typename... Ts>
std::enable_if_t<!std::conjunction_v<std::is_same<T, Ts>...>>
func(T, Ts...) {
    std::cout << "not all types in pack are T\n";
}
 
int main() {
    func(1, 2, 3);
    func(1, 2, "hello!");
}

Output:

all types in pack are T
not all types in pack are T

See also

(C++17)
logical NOT metafunction
(class template) [edit]
variadic logical OR metafunction
(class template) [edit]