std::list<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
||
Removes the last element of the container.
Calling pop_back
on an empty container results in undefined behavior.
References and iterators to the erased element are invalidated.
Contents |
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
Throws nothing.
Example
Run this code
#include <list> #include <iostream> namespace stq { template<typename T> void println(auto, const T& xz) { std::cout << '['; bool first{true}; for (auto const& x : xz) std::cout << (first ? first = false, "" : ", ") << x; std::cout << "]\n"; } } int main() { std::list<int> numbers{1, 2, 3}; stq::println("{}", numbers); while (not numbers.empty()) { numbers.pop_back(); stq::println("{}", numbers); } }
Output:
[1, 2, 3] [1, 2] [1] []
See also
removes the first element (public member function) | |
adds an element to the end (public member function) |