std::is_copy_assignable, std::is_trivially_copy_assignable, std::is_nothrow_copy_assignable
Defined in header <type_traits>
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template< class T > struct is_copy_assignable; |
(1) | (since C++11) |
template< class T > struct is_trivially_copy_assignable; |
(2) | (since C++11) |
template< class T > struct is_nothrow_copy_assignable; |
(3) | (since C++11) |
Type trait | The value of the member constant value
| |
---|---|---|
T is a referenceable type
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T is not a referenceable type
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(1) | std::is_assignable<T&, const T&>::value | false |
(2) | std::is_trivially_assignable<T&, const T&>::value | |
(3) | std::is_nothrow_assignable<T&, const T&>::value |
If T
is not a complete type, (possibly cv-qualified) void, or an array of unknown bound, the behavior is undefined.
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
If the program adds specializations for any of the templates described on this page, the behavior is undefined.
Contents |
Helper variable templates
template< class T > inline constexpr bool is_copy_assignable_v = |
(since C++17) | |
template< class T > inline constexpr bool is_trivially_copy_assignable_v = |
(since C++17) | |
template< class T > inline constexpr bool is_nothrow_copy_assignable_v = |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is copy-assignable, false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool |
type
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std::integral_constant<bool, value> |
Possible implementation
template<class T> struct is_copy_assignable : std::is_assignable<typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template<class T> struct is_trivially_copy_assignable : std::is_trivially_assignable<typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template<class T> struct is_nothrow_copy_assignable : std::is_nothrow_assignable<typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; |
Notes
The trait std::is_copy_assignable
is less strict than CopyAssignable because it does not check the type of the result of the assignment (which, for a CopyAssignable type, must be an lvalue of type T
) and does not check the semantic requirement that the argument expression remains unchanged. It also does not check that T
satisfies MoveAssignable, which is required of all CopyAssignable types.
Example
#include <iostream> #include <type_traits> #include <utility> struct Foo { int n; }; int main() { std::cout << std::boolalpha << "Foo is trivially copy-assignable? " << std::is_trivially_copy_assignable<Foo>::value << '\n' << "int[2] is copy-assignable? " << std::is_copy_assignable<int[2]>::value << '\n' << "int is nothrow copy-assignable? " << std::is_nothrow_copy_assignable<int>::value << '\n'; }
Output:
Foo is trivially copy-assignable? true int[2] is copy-assignable? false int is nothrow copy-assignable? true
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2196 | C++11 | the behavior was unclear if const T& cannot be formed | the value produced is false in this case |
See also
(C++11)(C++11)(C++11) |
checks if a type has an assignment operator for a specific argument (class template) |
(C++11)(C++11)(C++11) |
checks if a type has a move assignment operator (class template) |