std::equal_range
Defined in header <algorithm>
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||
(1) | ||
template< class ForwardIt, class T > std::pair<ForwardIt, ForwardIt> |
(constexpr since C++20) (until C++26) |
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template< class ForwardIt, class T = typename std::iterator_traits <ForwardIt>::value_type > |
(since C++26) | |
(2) | ||
template< class ForwardIt, class T, class Compare > std::pair<ForwardIt, ForwardIt> |
(constexpr since C++20) (until C++26) |
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template< class ForwardIt, class T = typename std::iterator_traits <ForwardIt>::value_type, |
(since C++26) | |
Returns a range containing all elements equivalent to value in the partitioned range [
first,
last)
.
Returns the results of std::lower_bound(first, last, value) and std::upper_bound(first, last, value). If any of the following conditions is satisfied, the behavior is undefined:
|
(until C++20) |
Equivalent to std::equal_range(first, last, value, std::less{}). |
(since C++20) |
- For any element elem of
[
first,
last)
, bool(comp(elem, value)) does not imply !bool(comp(value, elem)). - The elements elem of
[
first,
last)
are not partitioned with respect to expressions bool(comp(elem, value)) and !bool(comp(value, elem)).
Contents |
[edit] Parameters
first, last | - | the partitioned range of elements to examine |
value | - | value to compare the elements to |
comp | - | binary predicate which returns true if the first argument is ordered before the second. The signature of the predicate function should be equivalent to the following: bool pred(const Type1 &a, const Type2 &b); While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator.
| ||
-Compare must meet the requirements of BinaryPredicate. It is not required to satisfy Compare.
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[edit] Return value
A std::pair containing a pair of iterators, where
-
first
is an iterator to the first element of the range[
first,
last)
not ordered before value (or last if no such element is found), and -
second
is an iterator to the first element of the range[
first,
last)
ordered after value (or last if no such element is found).
[edit] Complexity
Given N as std::distance(first, last):
However, if ForwardIt
is not a LegacyRandomAccessIterator, the number of iterator increments is linear in N. Notably, std::set and std::multiset iterators are not random access, and so their member functions std::set::equal_range (resp. std::multiset::equal_range) should be preferred.
[edit] Notes
Although std::equal_range
only requires [
first,
last)
to be partitioned, this algorithm is usually used in the case where [
first,
last)
is sorted, so that the binary search is valid for any value.
On top of the requirements of std::lower_bound and std::upper_bound, std::equal_range
also requires operator< or comp to be asymmetric (i.e., a < b and b < a always have different results).
Therefore, the intermediate results of binary search can be shared by std::lower_bound and std::upper_bound. For example, the result of the std::lower_bound call can be used as the argument of first
in the std::upper_bound call.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_algorithm_default_value_type |
202403 | (C++26) | List-initialization for algorithms (1,2) |
[edit] Possible implementation
equal_range (1) |
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template<class ForwardIt, class T = typename std::iterator_traits<ForwardIt>::value_type> constexpr std::pair<ForwardIt, ForwardIt> equal_range(ForwardIt first, ForwardIt last, const T& value) { return std::equal_range(first, last, value, std::less{}); } |
equal_range (2) |
template<class ForwardIt, class T = typename std::iterator_traits<ForwardIt>::value_type, class Compare> constexpr std::pair<ForwardIt, ForwardIt> equal_range(ForwardIt first, ForwardIt last, const T& value, Compare comp) { return std::make_pair(std::lower_bound(first, last, value, comp), std::upper_bound(first, last, value, comp)); } |
[edit] Example
#include <algorithm> #include <complex> #include <iostream> #include <vector> struct S { int number; char name; // note: name is ignored by this comparison operator bool operator<(const S& s) const { return number < s.number; } }; struct Comp { bool operator()(const S& s, int i) const { return s.number < i; } bool operator()(int i, const S& s) const { return i < s.number; } }; int main() { // note: not ordered, only partitioned w.r.t. S defined below const std::vector<S> vec{{1, 'A'}, {2, 'B'}, {2, 'C'}, {2, 'D'}, {4, 'G'}, {3, 'F'}}; const S value{2, '?'}; std::cout << "Compare using S::operator<(): "; const auto p = std::equal_range(vec.begin(), vec.end(), value); for (auto it = p.first; it != p.second; ++it) std::cout << it->name << ' '; std::cout << '\n'; std::cout << "Using heterogeneous comparison: "; const auto p2 = std::equal_range(vec.begin(), vec.end(), 2, Comp{}); for (auto it = p2.first; it != p2.second; ++it) std::cout << it->name << ' '; std::cout << '\n'; using CD = std::complex<double>; std::vector<CD> nums{{1, 0}, {2, 2}, {2, 1}, {3, 0}, {3, 1}}; auto cmpz = [](CD x, CD y) { return x.real() < y.real(); }; #ifdef __cpp_lib_algorithm_default_value_type auto p3 = std::equal_range(nums.cbegin(), nums.cend(), {2, 0}, cmpz); #else auto p3 = std::equal_range(nums.cbegin(), nums.cend(), CD{2, 0}, cmpz); #endif for (auto it = p3.first; it != p3.second; ++it) std::cout << *it << ' '; std::cout << '\n'; }
Output:
Compare using S::operator<(): B C D Using heterogeneous comparison: B C D (2,2) (2, 1)
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 270 | C++98 | Compare was required to satisfy Compare and T was requiredto be LessThanComparable (strict weak ordering required) |
only a partitioning is required; heterogeneous comparisons permitted |
LWG 384 | C++98 | at most 2log2(N)+1 comparisons were allowed, which is not implementable[1] |
corrected to 2log2(N)+O(1) |
- ↑ Applying
equal_range
to a single-element range requires 2 comparisons, but at most 1 comparison is allowed by the complexity requirement.
[edit] See also
returns an iterator to the first element not less than the given value (function template) | |
returns an iterator to the first element greater than a certain value (function template) | |
determines if an element exists in a partially-ordered range (function template) | |
divides a range of elements into two groups (function template) | |
determines if two sets of elements are the same (function template) | |
returns range of elements matching a specific key (public member function of std::set<Key,Compare,Allocator> )
| |
returns range of elements matching a specific key (public member function of std::multiset<Key,Compare,Allocator> )
| |
(C++20) |
returns range of elements matching a specific key (niebloid) |