std::shift_left, std::shift_right
Defined in header <algorithm>
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template< class ForwardIt > constexpr ForwardIt shift_left( ForwardIt first, ForwardIt last, |
(1) | (since C++20) |
template< class ExecutionPolicy, class ForwardIt > ForwardIt shift_left( ExecutionPolicy&& policy, |
(2) | (since C++20) |
template< class ForwardIt > constexpr ForwardIt shift_right( ForwardIt first, ForwardIt last, |
(3) | (since C++20) |
template< class ExecutionPolicy, class ForwardIt > ForwardIt shift_right( ExecutionPolicy&& policy, |
(4) | (since C++20) |
Shifts the elements in the range [
first,
last)
by n positions.
- If n == 0 || n >= last - first, there are no effects.
- Otherwise, for every integer i in
[
0,
last - first - n)
, moves the element originally at position first + n + i to position first + i.
i
starting from 0.- If n == 0 || n >= last - first, there are no effects.
- Otherwise, for every integer i in
[
0,
last - first - n)
, moves the element originally at position first + i to position first + n + i.
ForwardIt
meets the LegacyBidirectionalIterator requirements, then the moves are performed in decreasing order of i starting from last - first - n - 1.Elements that are in the original range but not the new range are left in a valid but unspecified state.
If any of the following conditions is satisfied, the behavior is undefined:
- n >= 0 is not true.
- The type of *first is not MoveAssignable.
- For
shift_right
,ForwardIt
is neither LegacyBidirectionalIterator nor ValueSwappable.
Contents |
[edit] Parameters
first | - | the beginning of the original range |
last | - | the end of the original range |
n | - | the number of positions to shift |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator.
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[edit] Return value
- If n is less than std::distance(first, last), returns an iterator equal to std::next(first, (std::distance(first, last) - n)).
- Otherwise, returns first.
- If n is less than std::distance(first, last), returns an iterator equal to std::next(first, n).
- Otherwise, returns last.
[edit] Complexity
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit] Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_shift |
201806L | (C++20) | std::shift_left and std::shift_right
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[edit] Example
#include <algorithm> #include <iostream> #include <string> #include <type_traits> #include <vector> struct S { int value{0}; bool specified_state{true}; S(int v = 0) : value{v} {} S(S const& rhs) = default; S(S&& rhs) { *this = std::move(rhs); } S& operator=(S const& rhs) = default; S& operator=(S&& rhs) { if (this != &rhs) { value = rhs.value; specified_state = rhs.specified_state; rhs.specified_state = false; } return *this; } }; template<typename T> std::ostream& operator<<(std::ostream& os, std::vector<T> const& v) { for (const auto& s : v) { if constexpr (std::is_same_v<T, S>) s.specified_state ? os << s.value << ' ' : os << ". "; else if constexpr (std::is_same_v<T, std::string>) os << (s.empty() ? "." : s) << ' '; else os << s << ' '; } return os; } int main() { std::cout << std::left; std::vector<S> a{1, 2, 3, 4, 5, 6, 7}; std::vector<int> b{1, 2, 3, 4, 5, 6, 7}; std::vector<std::string> c{"α", "β", "γ", "δ", "ε", "ζ", "η"}; std::cout << "vector<S> \tvector<int> \tvector<string>\n"; std::cout << a << " " << b << " " << c << '\n'; std::shift_left(begin(a), end(a), 3); std::shift_left(begin(b), end(b), 3); std::shift_left(begin(c), end(c), 3); std::cout << a << " " << b << " " << c << '\n'; std::shift_right(begin(a), end(a), 2); std::shift_right(begin(b), end(b), 2); std::shift_right(begin(c), end(c), 2); std::cout << a << " " << b << " " << c << '\n'; std::shift_left(begin(a), end(a), 8); // has no effect: n >= last - first std::shift_left(begin(b), end(b), 8); // ditto std::shift_left(begin(c), end(c), 8); // ditto std::cout << a << " " << b << " " << c << '\n'; // std::shift_left(begin(a), end(a), -3); // UB, e.g. segfault }
Possible output:
vector<S> vector<int> vector<string> 1 2 3 4 5 6 7 1 2 3 4 5 6 7 α β γ δ ε ζ η 4 5 6 7 . . . 4 5 6 7 5 6 7 δ ε ζ η . . . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η .
[edit] See also
(C++11) |
moves a range of elements to a new location (function template) |
(C++11) |
moves a range of elements to a new location in backwards order (function template) |
rotates the order of elements in a range (function template) | |
shifts elements in a range (niebloid) |