std::common_type<std::chrono::duration>
From cppreference.com
Defined in header <chrono>
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template< class Rep1, class Period1, class Rep2, class Period2 > struct common_type<std::chrono::duration<Rep1, Period1>, |
(since C++11) | |
Exposes the type named type
, which is the common type of two std::chrono::durations, whose period is the greatest common divisor of Period1
and Period2
.
Contents |
[edit] Member types
Member type | Definition |
type
|
std::chrono::duration<typename std::common_type<Rep1, Rep2>::type, /* see note */> |
[edit] Note
The period of the resulting duration can be computed by forming a ratio of the greatest common divisor of Period1::num and Period2::num and the least common multiple of Period1::den and Period2::den.
[edit] Example
Run this code
#include <chrono> #include <iostream> #include <type_traits> // std::chrono already finds the greatest common divisor, // likely using std::common_type<>. We make the type // deduction externally. template<typename T,typename S> constexpr auto durationDiff(const T& t, const S& s) -> typename std::common_type<T,S>::type { typedef typename std::common_type<T,S>::type Common; return Common(t) - Common(s); } int main() { using namespace std::literals; constexpr auto ms = 30ms; constexpr auto us = 1100us; constexpr auto diff = durationDiff(ms, us); std::cout << ms << " - " << us << " = " << diff << '\n'; }
Output:
30ms - 1100us = 28900us
[edit] See also
specializes the std::common_type trait (class template specialization) | |
(C++11) |
determines the common type of a group of types (class template) |