std::chrono::weekday::operator+=, std::chrono::weekday::operator-=
From cppreference.com
constexpr std::chrono::weekday& operator+=( const std::chrono::days& d ) noexcept; |
(1) | (since C++20) |
constexpr std::chrono::weekday& operator-=( const std::chrono::days& d ) noexcept; |
(2) | (since C++20) |
Adds or subtracts d.count() from the weekday value, reducing the result modulo 7 to an integer in the range [
0,
6]
.
1) Performs *this = *this + d;.
2) Performs *this = *this - d;.
Contents |
[edit] Return value
A reference to this weekday
after modification.
[edit] Notes
After a call to one of these functions, ok() is always true if no overflow occurred during the operation.
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { std::cout << std::boolalpha; std::chrono::weekday wd{5}; // Friday is 5 wd += std::chrono::days(2); std::cout << (wd == std::chrono::weekday(0)) << ' ' << (wd == std::chrono::Sunday) << ' '; wd -= std::chrono::days(3); std::cout << (wd == std::chrono::weekday(4)) << ' ' << (wd == std::chrono::Thursday) << ' '; wd = std::chrono::Wednesday; wd += std::chrono::days{8}; // ((3 += 8 == 11) % 7) == 4; std::cout << (wd == std::chrono::Thursday) << ' '; wd -= (std::chrono::Sunday - std::chrono::Tuesday); // -= -2 // (4 -= -2) == 6 std::cout << (wd == std::chrono::Saturday) << '\n'; }
Output:
true true true true true true
[edit] See also
increments or decrements the weekday (public member function) | |
(C++20) |
performs arithmetic on weekday s (function) |