std::deque<T,Allocator>::erase
(1) | ||
iterator erase( iterator pos ); |
(until C++11) | |
iterator erase( const_iterator pos ); |
(since C++11) | |
(2) | ||
iterator erase( iterator first, iterator last ); |
(until C++11) | |
iterator erase( const_iterator first, const_iterator last ); |
(since C++11) | |
Erases the specified elements from the container.
[
first,
last)
.All iterators and references are invalidated, unless the erased elements are at the end or at the beginning of the container, in which case only the iterators and references to the erased elements are invalidated. The end()
iterator is also invalidated unless the erased elements are at the beginning of the container and the last element is not erased.
The iterator pos must be valid and dereferenceable. Thus the end() iterator (which is valid, but is not dereferenceable) cannot be used as a value for pos.
The iterator first does not need to be dereferenceable if first == last: erasing an empty range is a no-op.
Contents |
[edit] Parameters
pos | - | iterator to the element to remove |
first, last | - | range of elements to remove |
Type requirements | ||
-T must meet the requirements of MoveAssignable.
|
[edit] Return value
Iterator following the last removed element.
[
first,
last)
is an empty range, then last is returned.[edit] Exceptions
Does not throw unless an exception is thrown by the assignment operator of T
.
[edit] Complexity
Linear: the number of calls to the destructor of T
is the same as the number of elements erased, the number of calls to the assignment operator of T
is no more than the lesser of the number of elements before the erased elements and the number of elements after the erased elements.
[edit] Notes
When container elements need to be erased based on a predicate, rather than iterating the container and calling unary erase
, the iterator range overload is generally used with std::remove()/std::remove_if() to minimise the number of moves of the remaining (non-removed) elements, — this is the erase-remove idiom.
std::erase_if()
replaces the erase-remove idiom.(since C++20)
[edit] Example
#include <deque> #include <iostream> void print_container(const std::deque<int>& c) { for (int i : c) std::cout << i << ' '; std::cout << '\n'; } int main() { std::deque<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; print_container(c); c.erase(c.begin()); print_container(c); c.erase(c.begin() + 2, c.begin() + 5); print_container(c); // Erase all even numbers for (std::deque<int>::iterator it = c.begin(); it != c.end();) { if (*it % 2 == 0) it = c.erase(it); else ++it; } print_container(c); }
Output:
0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 6 7 8 9 1 7 9
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 151 | C++98 | first was required to be dereferenceable, which made the behavior of clearing an empty deque undefined
|
not required if first == last |
LWG 638 | C++98 | the past-the-end iterator was not invalidated | it is invalidated if the elements are erased from the middle or the end |
[edit] See also
erases all elements satisfying specific criteria (function template) | |
clears the contents (public member function) |