std::flat_map<Key,T,Compare,KeyContainer,MappedContainer>::operator[]
From cppreference.com
T& operator[]( const Key& key ); |
(1) | (since C++23) |
T& operator[]( Key&& key ); |
(2) | (since C++23) |
template< class K > T& operator[]( K&& x ); |
(3) | (since C++23) |
Returns a reference to the value that is mapped to a key equivalent to key or x respectively, performing an insertion if such key does not already exist.
1) Inserts a
value_type
object constructed in-place if the key does not exist. Equivalent to return try_emplace(x).first->second;.2) Inserts a
value_type
object constructed in-place if the key does not exist. Equivalent to return try_emplace(std::move(x)).first->second;3) Inserts a
value_type
object constructed in-place if there is no key that transparently compares equivalent to the value x. Equivalent to return this->try_emplace(std::forward<K>(x)).first->second;.
This overload participates in overload resolution only if the qualified-id Compare::is_transparent is valid and denotes a type. It allows calling this function without constructing an instance of
Key
.Information on iterator invalidation is copied from here |
Contents |
[edit] Parameters
key | - | the key of the element to find |
x | - | a value of any type that can be transparently compared with a key |
[edit] Return value
1,2) A reference to the mapped value of the new element if no element with key key existed. Otherwise, a reference to the mapped value of the existing element whose key is equivalent to key.
3) A reference to the mapped value of the new element if no element with key that compares equivalent to the value x existed. Otherwise, a reference to the mapped value of the existing element whose key compares equivalent to x.
[edit] Exceptions
If an exception is thrown by any operation, the insertion has no effect.
[edit] Complexity
Logarithmic in the size of the container, plus the cost of insertion (if any) of an empty element.
[edit] Notes
operator[] is non-const because it inserts the key if it doesn't exist. If this behavior is undesirable or if the container is const, at
may be used.
insert_or_assign
returns more information than operator[] and does not require default-constructibility of the mapped type.
[edit] Example
Run this code
#include <iostream> #include <string> #include <flat_map> void println(auto const comment, auto const& map) { std::cout << comment << '{'; for (const auto& pair : map) std::cout << '{' << pair.first << ": " << pair.second << '}'; std::cout << "}\n"; } int main() { std::flat_map<char, int> letter_counts{{'a', 27}, {'b', 3}, {'c', 1}}; println("letter_counts initially contains: ", letter_counts); letter_counts['b'] = 42; // updates an existing value letter_counts['x'] = 9; // inserts a new value println("after modifications it contains: ", letter_counts); // count the number of occurrences of each word // (the first call to operator[] initialized the counter with zero) std::flat_map<std::string, int> word_map; for (const auto& w : {"this", "sentence", "is", "not", "a", "sentence", "this", "sentence", "is", "a", "hoax"}) ++word_map[w]; word_map["that"]; // just inserts the pair {"that", 0} for (const auto& [word, count] : word_map) std::cout << count << " occurrence(s) of word '" << word << "'\n"; }
Output:
letter_counts initially contains: {{a: 27}{b: 3}{c: 1}} after modifications it contains: {{a: 27}{b: 42}{c: 1}{x: 9}} 2 occurrence(s) of word 'a' 1 occurrence(s) of word 'hoax' 2 occurrence(s) of word 'is' 1 occurrence(s) of word 'not' 3 occurrence(s) of word 'sentence' 0 occurrence(s) of word 'that' 2 occurrence(s) of word 'this'
[edit] See also
access specified element with bounds checking (public member function) | |
inserts an element or assigns to the current element if the key already exists (public member function) | |
inserts in-place if the key does not exist, does nothing if the key exists (public member function) |