std::bit_cast
Defined in header <bit>
|
||
template< class To, class From > constexpr To bit_cast( const From& from ) noexcept; |
(since C++20) | |
Obtain a value of type To
by reinterpreting the object representation of From
. Every bit in the value representation of the returned To
object is equal to the corresponding bit in the object representation of from. The values of padding bits in the returned To
object are unspecified.
If there is no value of type To
corresponding to the value representation produced, the behavior is undefined. If there are multiple such values, which value is produced is unspecified.
A bit in the value representation of the result is indeterminate if it
- does not correspond to a bit in the value representation of
From
(i.e. it corresponds to a padding bit), or - corresponds to a bit of an object that(until C++26)for which the smallest enclosing object(since C++26) is not within its lifetime, or
- has an indeterminate value.
A bit in the value representation of the result is erroneous if it corresponds to a bit for which the smallest enclosing object has an erroneous value. |
(since C++26) |
For each bit in the value representation of the result that is indeterminate, the smallest object containing that bit has an indeterminate value; the behavior is undefined unless that object is of an uninitialized-friendly type. The result does not otherwise contain any indeterminate values. |
(until C++26) |
For each bit b in the value representation of the result that is indeterminate or erroneous, let u be the smallest object enclosing b:
|
(since C++26) |
This overload participates in overload resolution only if sizeof(To) == sizeof(From) and both To
and From
are TriviallyCopyable types.
This function template is constexpr if and only if each of To
, From
and the types of all subobjects of To
and From
:
- is not a union type;
- is not a pointer type;
- is not a pointer to member type;
- is not a volatile-qualified type; and
- has no non-static data member of reference type.
Contents |
[edit] Parameters
from | - | the source of bits for the return value |
[edit] Return value
An object of type To
whose value representation is as described above.
[edit] Possible implementation
To implement std::bit_cast
, ignoring the fact that it's constexpr, std::memcpy can be used, when it is needed, to interpret the object representation as one of another type:
template<class To, class From> std::enable_if_t< sizeof(To) == sizeof(From) && std::is_trivially_copyable_v<From> && std::is_trivially_copyable_v<To>, To> // constexpr support needs compiler magic bit_cast(const From& src) noexcept { static_assert(std::is_trivially_constructible_v<To>, "This implementation additionally requires " "destination type to be trivially constructible"); To dst; std::memcpy(&dst, &src, sizeof(To)); return dst; }
[edit] Notes
reinterpret_cast (or equivalent explicit cast) between pointer or reference types shall not be used to reinterpret object representation in most cases because of the type aliasing rule.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_bit_cast |
201806L | (C++20) | std::bit_cast
|
[edit] Example
#include <bit> #include <cstdint> #include <iostream> constexpr double f64v = 19880124.0; constexpr auto u64v = std::bit_cast<std::uint64_t>(f64v); static_assert(std::bit_cast<double>(u64v) == f64v); // round-trip constexpr std::uint64_t u64v2 = 0x3fe9000000000000ull; constexpr auto f64v2 = std::bit_cast<double>(u64v2); static_assert(std::bit_cast<std::uint64_t>(f64v2) == u64v2); // round-trip int main() { std::cout << "std::bit_cast<std::uint64_t>(" << std::fixed << f64v << ") == 0x" << std::hex << u64v << '\n' << "std::bit_cast<double>(0x" << std::hex << u64v2 << ") == " << std::fixed << f64v2 << '\n'; }
Possible output:
std::bit_cast<std::uint64_t>(19880124.000000) == 0x4172f58bc0000000 std::bit_cast<double>(0x3fe9000000000000) == 0.781250
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 2482 (P1272R4) |
C++20 | it was unspecified whether UB would occur when involving indeterminate bits | specified |
[edit] See also
implicitly creates objects in given storage with the object representation reused (function template) |