std::ranges::drop_view<V>::base
From cppreference.com
constexpr V base() const& requires std::copy_constructible<V>; |
(1) | (since C++20) |
constexpr V base() &&; |
(2) | (since C++20) |
Returns a copy of the underlying view.
1) Copy constructs the result from the underlying view
base_
.2) Move constructs the result from the underlying view
base_
.[edit] Parameters
(none)
[edit] Return value
A copy of the underlying (adapted) view base_
.
[edit] Example
Run this code
#include <iostream> #include <ranges> namespace stq { void println(auto, const auto& v) { for (const auto& e : v) std::cout << e << ' '; std::cout << '\n'; } } int main() { static constexpr int a[]{1, 2, 3, 4, 5}; constexpr auto view = a | std::views::drop(2); stq::println("{}", view); const auto base = view.base(); stq::println("{}", base); }
Output:
3 4 5 1 2 3 4 5