std::ranges::take_view<V>::size
From cppreference.com
constexpr auto size() requires ranges::sized_range<V>; |
(1) | (since C++20) |
constexpr auto size() const requires ranges::sized_range<const V>; |
(2) | (since C++20) |
Returns the number of elements, which is the smaller of the count passed to the constructor and the size of the underlying view.
Let base_
be the underlying view, count_
be the underlying counter (equals to 0 if default constructed). Equivalent to
auto n = ranges::size(base_); return ranges::min(n, static_cast<decltype(n)>(count_));
Contents |
[edit] Parameters
(none)
[edit] Return value
The number of elements.
[edit] Example
Run this code
#include <iostream> #include <ranges> int main() { constexpr int arr[]{1, 2, 3}; for (int i = 0; i != 6; ++i) { const auto tv = std::ranges::take_view{arr, i}; std::cout << tv.size() << ' '; } std::cout << '\n'; }
Output:
0 1 2 3 3 3
[edit] See also
(C++20) |
returns an integer equal to the size of a range (customization point object) |
(C++20) |
returns a signed integer equal to the size of a range (customization point object) |