std::is_const
From cppreference.com
Defined in header <type_traits>
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template< class T > struct is_const; |
(since C++11) | |
std::is_const
is a UnaryTypeTrait.
If T
is a const-qualified type (that is, const, or const volatile), provides the member constant value equal to true. For any other type, value is false.
If the program adds specializations for std::is_const
or std::is_const_v
, the behavior is undefined.
Contents |
[edit] Template parameters
T | - | a type to check |
[edit] Helper variable template
template< class T > constexpr bool is_const_v = is_const<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is a const-qualified type, false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
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bool |
type
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std::integral_constant<bool, value> |
[edit] Notes
If T is a reference type then is_const<T>::value is always false. The proper way to check a potentially-reference type for constness is to remove the reference: is_const<typename remove_reference<T>::type>.
[edit] Possible implementation
template<class T> struct is_const : std::false_type {}; template<class T> struct is_const<const T> : std::true_type {}; |
[edit] Example
Run this code
#include <type_traits> static_assert(std::is_same_v<const int*, int const*>, "Remember, constness binds tightly inside pointers."); static_assert(!std::is_const_v<int>); static_assert(std::is_const_v<const int>); static_assert(!std::is_const_v<int*>); static_assert(std::is_const_v<int* const>, "Because the pointer itself can't be changed but the int pointed at can."); static_assert(!std::is_const_v<const int*>, "Because the pointer itself can be changed but not the int pointed at."); static_assert(!std::is_const_v<const int&>); static_assert(std::is_const_v<std::remove_reference_t<const int&>>); struct S { void foo() const {} void bar() const {} }; int main() { // A const member function is const in a different way: static_assert(!std::is_const_v<decltype(&S::foo)>, "Because &S::foo is a pointer."); using S_mem_fun_ptr = void(S::*)() const; S_mem_fun_ptr sfp = &S::foo; sfp = &S::bar; // OK, can be re-pointed static_assert(!std::is_const_v<decltype(sfp)>, "Because sfp is the same pointer type and thus can be re-pointed."); const S_mem_fun_ptr csfp = &S::foo; // csfp = &S::bar; // Error static_assert(std::is_const_v<decltype(csfp)>, "Because csfp cannot be re-pointed."); }
[edit] See also
(C++11) |
checks if a type is volatile-qualified (class template) |
(C++17) |
obtains a reference to const to its argument (function template) |