operator&,|,^(std::bitset)
From cppreference.com
Defined in header <bitset>
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template< std::size_t N > std::bitset<N> operator&( const std::bitset<N>& lhs, |
(1) | (noexcept since C++11) (constexpr since C++23) |
template< std::size_t N > std::bitset<N> operator|( const std::bitset<N>& lhs, |
(2) | (noexcept since C++11) (constexpr since C++23) |
template< std::size_t N > std::bitset<N> operator^( const std::bitset<N>& lhs, |
(3) | (noexcept since C++11) (constexpr since C++23) |
Performs binary AND, OR, and XOR between two bitsets, lhs and rhs.
1) Returns a std::bitset<N> containing the result of binary AND on corresponding pairs of bits of lhs and rhs.
2) Returns a std::bitset<N> containing the result of binary OR on corresponding pairs of bits of lhs and rhs.
3) Returns a std::bitset<N> containing the result of binary XOR on corresponding pairs of bits of lhs and rhs.
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[edit] Parameters
lhs | - | the bitset on the left-hand side of the operator |
rhs | - | the bitset on the right-hand side of the operator |
[edit] Return value
1) std::bitset<N>(lhs) &= rhs
2) std::bitset<N>(lhs) |= rhs
3) std::bitset<N>(lhs) ^= rhs
[edit] Example
Run this code
#include <bitset> #include <iostream> int main() { std::bitset<4> b1("0110"); std::bitset<4> b2("0011"); std::cout << "b1 & b2: " << (b1 & b2) << '\n'; std::cout << "b1 | b2: " << (b1 | b2) << '\n'; std::cout << "b1 ^ b2: " << (b1 ^ b2) << '\n'; }
Output:
b1 & b2: 0010 b1 | b2: 0111 b1 ^ b2: 0101
[edit] See also
performs binary AND, OR, XOR and NOT (public member function) |