std::make_pair
From cppreference.com
Defined in header <utility>
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template< class T1, class T2 > std::pair<T1, T2> make_pair( T1 x, T2 y ); |
(until C++11) | |
template< class T1, class T2 > std::pair</*V1*/, /*V2*/> make_pair( T1&& x, T2&& y ); |
(since C++11) (constexpr since C++14) (until C++20) |
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template< class T1, class T2 > constexpr std::pair<std::unwrap_ref_decay_t<T1>, |
(since C++20) | |
Creates a std::pair object, deducing the target type from the types of arguments.
Given types std::decay<T1>::type as
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(since C++11) (until C++20) |
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[edit] Parameters
x, y | - | the values to construct the pair from |
[edit] Return value
std::pair<T1, T2>(x, y) |
(until C++11) |
std::pair</*V1*/, /*V2*/>(std::forward<T1>(x), std::forward<T2>(y)) |
(since C++11) (until C++20) |
std::pair<std::unwrap_ref_decay_t<T1>, std::unwrap_ref_decay_t<T2>> |
(since C++20) |
[edit] Example
Run this code
#include <functional> #include <iostream> #include <utility> int main() { int n = 1; int a[5] = {1, 2, 3, 4, 5}; // build a pair from two ints auto p1 = std::make_pair(n, a[1]); std::cout << "The value of p1 is " << '(' << p1.first << ", " << p1.second << ")\n"; // build a pair from a reference to int and an array (decayed to pointer) auto p2 = std::make_pair(std::ref(n), a); n = 7; std::cout << "The value of p2 is " << '(' << p2.first << ", " << *(p2.second + 2) << ")\n"; }
Output:
The value of p1 is (1, 2) The value of p2 is (7, 3)
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
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LWG 181 | C++98 | the parameter types were const-reference types, which made passing arrays impossible |
changed these types to value types |