std::source_location::line
From cppreference.com
< cpp | utility | source location
constexpr std::uint_least32_t line() const noexcept; |
(since C++20) | |
Returns the line number represented by this object.
Contents |
[edit] Parameters
(none)
[edit] Return value
The line number represented by this object.
An implementation is encouraged to return 0
when the line number is unknown.
[edit] Example
Run this code
#include <iostream> #include <string_view> #include <source_location> inline void cur_line( const std::string_view message = "", const std::source_location& location = std::source_location::current()) { std::cout << location.line() // <- the line # of a call site << ") " << message; } int main() { cur_line("++\n"); cur_line(); std::cout << "Hello,\n"; cur_line(); std::cout << "C++20!\n"; cur_line("--\n"); }
Output:
17) ++ 18) Hello, 19) C++20! 20) --
[edit] See also
return the column number represented by this object (public member function) | |
return the file name represented by this object (public member function) | |
return the name of the function represented by this object, if any (public member function) | |
gets the line number that lexically relates the evaluation represented by the stacktrace_entry (public member function of std::stacktrace_entry )
| |
Filename and line information |