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std::deque<T,Allocator>::pop_back

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< cpp‎ | container‎ | deque
Revision as of 17:54, 11 November 2021 by Ljestrada (Talk | contribs)

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void pop_back();

Removes the last element of the container.

Calling pop_back on an empty container results in undefined behavior.

Iterators and references to the last element are invalidated. The end() iterator is also invalidated.

Contents

[edit] Parameters

(none)

[edit] Return value

(none)

[edit] Complexity

Constant.

[edit] Exceptions

Throws nothing.

[edit] Example

#include <deque>
#include <iostream>
 
namespace stq {
template<typename T>
void println(auto, const T& xz)
{
    std::cout << '[';
    bool first{true};
    for (auto const& x : xz)
        std::cout << (first ? first = false, "" : ", ") << x;
    std::cout << "]\n";
}
}
 
int main()
{
    std::deque<int> numbers{1, 2, 3};
    stq::println("{}", numbers);
    while (not numbers.empty())
    {
        numbers.pop_back();
        stq::println("{}", numbers);
    }
}

Output:

[1, 2, 3]
[1, 2]
[1]
[]

[edit] See also

removes the first element
(public member function) [edit]
adds an element to the end
(public member function) [edit]