std::allocator_traits<Alloc>::allocate
[[nodiscard]] static constexpr std::allocation_result<pointer, size_type> allocate_at_least( Alloc& a, size_type n ); |
(since C++23) | |
allocate_at_least
calls a.allocate_at_least(n) and returns its result if the call is well-formed, otherwise, it is equivalent to return {a.allocate(n), n};.
allocator_at_least
tries to allocate a storage for at least n
value_type objects, and provides a fallback mechanism that allocates a storage for exact n
objects.
Contents |
Parameters
a | - | an allocator used for allocating storage |
n | - | the lower bound of number of objects to allocate storage for |
Return value
a.allocate_at_least(n) if it is well-formed.
Otherwise, std::allocation_result<pointer, size_type>{a.allocate(n), n}.
Exceptions
Throws what and when the selected allocation function throws.
Notes
The allocate_at_least
member function of Allocator types are mainly provided for contiguous containers, e.g. std::vector and std::basic_string, in order to reduce reallocation by making their capacity match the actually allocated size when possible. Because std::allocator_traits::allocate_at_least
provides a fallback mechanism, it can be directly used where appropriate.
Given an allocator object a
of type Alloc
, let result
denote the value returned from std::allocate_at_least(a, n), the storage should be deallocated by a.deallocate(result.ptr, m) (typically called via std::allocator_traits<Alloc>::deallocate(a, result.ptr, m)) in order to avoid memory leak.
The argument m
used in deallocation must be not less than n
and not greater than result.count, otherwise, the behavior is undefined. Note that n
is always equal to result.count if the allocator does not provide allocate_at_least
, which means that m
is required to be equal to n
.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_allocate_at_least |
202106L | (C++23) |
Example
This section is incomplete Reason: no example |
See also
(C++23) |
allocates uninitialized storage at least as large as requested size (public member function of std::allocator<T> )
|