std::inout_ptr
From cppreference.com
Defined in header <memory>
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template< class Pointer = void, class Smart, class... Args > auto inout_ptr( Smart& s, Args&&... args ); |
(since C++23) | |
Returns an inout_ptr_t
with deduced template arguments that captures arguments for resetting by reference.
The program is ill-formed if construction of the return value (see below) is ill-formed.
Contents |
Parameters
s | - | the object (typically a smart pointer) to adapt |
args... | - | the arguments for resetting to capture |
Return value
std::inout_ptr_t<Smart, P, Args&&>(s, std::forward<Args>(args)...), where P
is
-
Pointer
, ifPointer
is not same as void, otherwise, - Smart::pointer, if it is valid and denotes a type, otherwise,
- Smart::element_type*, if Smart::element_type is valid and denotes a type, otherwise,
- std::pointer_traits<Smart>::element_type*.
Notes
Users may specify the template argument for the template parameter Pointer
, in order to interoperate with foreign functions that take a Pointer*.
As all arguments for resetting are captured by reference, the returned inout_ptr_t
should be a temporary object destroyed at the end of the full-expression containing the call to the foreign function, in order to avoid dangling references.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_out_ptr |
202106L | (C++23) | std::out_ptr, std::inout_ptr
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Example
This section is incomplete Reason: no example |
See also
(C++23) |
creates an out_ptr_t with an associated smart pointer and resetting arguments (function template) |
(C++14)(C++20) |
creates a unique pointer that manages a new object (function template) |
creates a shared pointer that manages a new object (function template) |