std::pmr::polymorphic_allocator<T>::allocate_bytes
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Revision as of 02:48, 1 July 2024 by D41D8CD98F (Talk | contribs)
void* allocate_bytes( std::size_t nbytes, std::size_t alignment = alignof(std::max_align_t) ); |
(since C++20) | |
Allocates nbytes bytes of storage at specified alignment alignment using the underlying memory resource. Equivalent to return resource()->allocate(nbytes, alignment);.
Contents |
[edit] Parameters
nbytes | - | the number of bytes to allocate |
alignment | - | the alignment to use |
[edit] Return value
A pointer to the allocated storage.
[edit] Notes
This function was introduced for use with the fully-specialized allocator std::pmr::polymorphic_allocator<>, but it may be useful in any specialization.
The return type is void* (rather than, e.g., std::byte*) to support conversion to an arbitrary pointer type U* by static_cast<U*>.
[edit] Exceptions
May throw any exceptions thrown by the call to resource()->allocate.
[edit] See also
(C++20) |
allocates raw memory suitable for an object or an array (public member function) |
(C++20) |
allocates and constructs an object (public member function) |
allocate memory (public member function) | |
[static] |
allocates uninitialized storage using the allocator (public static member function of std::allocator_traits<Alloc> )
|
allocates memory (public member function of std::pmr::memory_resource )
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