std::basic_string<CharT,Traits,Allocator>::substr
From cppreference.com
| basic_string substr( size_type pos = 0, size_type count = npos ); |
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Returns a substring [pos, pos+count). If the requested substring lasts past the end of the string, or if count == npos, the returned substring is [pos, size()-pos).
Contents |
Parameters
| pos | - | position of the first character to include |
| count | - | length of the substring |
Return value
String containing the substring [pos, pos+count).
Exceptions
std::out_of_range if pos > size().
Complexity
Linear in count
Example
Run this code
#include <string> #include <iostream> int main() { std::string a = "0123456789abcdefghij"; std::string sub1 = a.substr(10); std::cout << sub1 << '\n'; std::string sub2 = a.substr(5, 3); std::cout << sub2 << '\n'; std::string sub3 = a.substr(12, 100); std::cout << sub3 << '\n'; }
Output:
abcdefghij 567 cdefghij
