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std::destroy_n

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Defined in header <memory>
template< class ForwardIt, class Size >
ForwardIt destroy_n( ForwardIt first, Size n );
(1) (since C++17)
template< class ExecutionPolicy, class ForwardIt, class Size >
ForwardIt destroy_n( ExecutionPolicy&& policy, ForwardIt first, Size n );
(2) (since C++17)
1) Destroys the n objects in the range starting at first, as if by
for (; n > 0; (void) ++first, --n)
  std::destroy_at(std::addressof(*first));
2) Same as (1), but executed according to policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true

Contents

Parameters

first - the beginning of the range of elements to destroy
n - the number of elements to destroy
policy - the execution policy to use. See execution policy for details.
Type requirements

Template:par req concept

-
No increment, assignment, comparison, or indirection through valid instances of ForwardIt may throw exceptions.

Return value

The end of the range of objects that has been destroyed (i.e., std::next(first, n)).

Complexity

Linear in n.

Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

  • If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
  • If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

template<class ForwardIt, class Size>
ForwardIt destroy_n( ForwardIt first, Size n )
{
  for (; n > 0; (void) ++first, --n)
    std::destroy_at(std::addressof(*first));
  return first;
}

Example

See also

(C++17)
destroys a range of objects
(function template) [edit]
destroys an object at a given address
(function template) [edit]