std::vector<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
(constexpr since C++20) | |
Removes the last element of the container.
Calling pop_back
on an empty container results in undefined behavior.
Iterators and references to the last element are invalidated. The end()
iterator is also invalidated.
Contents |
[edit] Parameters
(none)
[edit] Return value
(none)
[edit] Complexity
Constant.
[edit] Exceptions
Throws nothing.
[edit] Example
Run this code
#include <vector> #include <iostream> namespace stq { template<typename T> void println(auto, const T& xz) { std::cout << '['; bool first{true}; for (auto const& x : xz) std::cout << (first ? first = false, "" : ", ") << x; std::cout << "]\n"; } } int main() { std::vector<int> numbers{1, 2, 3}; stq::println("{}", numbers); while (not numbers.empty()) { numbers.pop_back(); stq::println("{}", numbers); } }
Output:
[1, 2, 3] [1, 2] [1] []
[edit] See also
adds an element to the end (public member function) |