std::ranges::elements_of
From cppreference.com
Defined in header <ranges>
|
||
template< ranges::range R, class Allocator = std::allocator<std::byte> > struct elements_of; |
(since C++23) | |
Encapsulates a range
. Specializations of elements_of
act as a tag in overload sets to disambiguate when a range should be treated as a sequence rather than a single value.
Contents |
Template parameters
R | - | a type that satisfies range
|
Allocator | - | an allocator type that meets the requirements of Allocator |
Data members
Member name | Definition |
range |
a range of type R (public member object) |
allocator |
an allocator of type Allocator . It has default member initializer that value initializes itself (public member object) |
All these members are declared with [[no_unique_address]]
attribute.
Deduction guide
template< class R, class Allocator = std::allocator<std::byte> > elements_of( R&&, Allocator = Allocator() ) -> elements_of<R&&, Allocator>; |
(since C++23) | |
Example
Run this code
#include <any> #include <generator> #include <iostream> #include <ranges> #include <string_view> template<bool Elementwise> std::generator<std::any> gen(std::ranges::input_range auto&& r) { if constexpr (Elementwise) co_yield std::ranges::elements_of(r); // yield each element of r else co_yield r; // yield r as a single value } int main() { auto test = std::string_view{"test"}; for (std::any a : gen<true>(test)) std::cout << '[' << std::any_cast<char>(a) << "] "; std::cout << '\n'; for (std::any a : gen<false>(test)) std::cout << '[' << std::any_cast<std::string_view>(a) << "] "; std::cout << '\n'; }
Output:
[t] [e] [s] [t] [test]
References
- C++23 standard (ISO/IEC 14882:2024):
- 26.5.6 Class template elements_of [range.elementsof]