std::erase, std::erase_if(std::list)
From cppreference.com
Defined in header <list>
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(1) | ||
(since C++20) (until C++26) |
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(since C++26) | ||
(2) | (since C++20) | |
1) Erases all elements that compare equal to value from the container. Equivalent to return c.remove_if([&](auto& elem) { return elem == value; });.
2) Erases all elements that satisfy the predicate pred from the container. Equivalent to return c.remove_if(pred);.
Contents |
[edit] Parameters
c | - | container from which to erase |
value | - | value to be removed |
pred | - | unary predicate which returns true if the element should be erased. The expression pred(v) must be convertible to bool for every argument |
[edit] Return value
The number of erased elements.
[edit] Complexity
Linear.
Notes
Unlike std::list::remove, erase
accepts heterogeneous types and does not force a conversion to the container's value type before invoking the == operator.
Feature-test macro | Value | Std | Feature |
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__cpp_lib_algorithm_default_value_type |
202403 | (C++26) | List-initialization for algorithm (1) |
[edit] Example
Run this code
#include <complex> #include <iostream> #include <numeric> #include <string_view> #include <list> void println(std::string_view comment, const auto& c) { std::cout << comment << '['; bool first{true}; for (const auto& x : c) std::cout << (first ? first = false, "" : ", ") << x; std::cout << "]\n"; } int main() { std::list<char> cnt(10); std::iota(cnt.begin(), cnt.end(), '0'); println("Initially, cnt = ", cnt); std::erase(cnt, '3'); println("After erase '3', cnt = ", cnt); auto erased = std::erase_if(cnt, [](char x) { return (x - '0') % 2 == 0; }); println("After erase all even numbers, cnt = ", cnt); std::cout << "Erased even numbers: " << erased << '\n'; std::list<std::complex<double>> nums{{2, 2}, {4, 2}, {4, 8}, {4, 2}}; #ifdef __cpp_lib_algorithm_default_value_type std::erase(nums, {4, 2}); #else std::erase(nums, std::complex<double>{4, 2}); #endif println("After erase {4, 2}, nums = ", nums); }
Output:
Initially, cnt = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] After erase '3', cnt = [0, 1, 2, 4, 5, 6, 7, 8, 9] After erase all even numbers, cnt = [1, 5, 7, 9] Erased even numbers: 5 After erase {4, 2}, nums = [(2,2), (4,8)]
[edit] See also
removes elements satisfying specific criteria (function template) | |
(C++20)(C++20) |
removes elements satisfying specific criteria (niebloid) |
removes elements satisfying specific criteria (public member function) |