std::shared_ptr<T>::get
From cppreference.com
< cpp | memory | shared ptr
T* get() const noexcept; |
(until C++17) | |
element_type* get() const noexcept; |
(since C++17) | |
Returns the stored pointer.
Contents |
[edit] Parameters
(none)
[edit] Return value
The stored pointer.
[edit] Notes
A shared_ptr
may share ownership of an object while storing a pointer to another object. get()
returns the stored pointer, not the managed pointer.
[edit] Example
Run this code
#include <iostream> #include <memory> #include <string_view> int main() { auto output = [](std::string_view msg, int const* pInt) { std::cout << msg << *pInt << " in " << pInt << '\n'; }; int* pInt = new int(42); std::shared_ptr<int> pShared = std::make_shared<int>(42); output("Naked pointer: ", pInt); // output("Shared pointer: ", pShared); // compiler error output("Shared pointer: ", &*pShared); // OK, calls operator*, then takes addr output("Shared pointer with get(): ", pShared.get()); delete pInt; std::cout << "\nThe shared_ptr's aliasing constructor demo.\n"; struct Base1 { int i1{}; }; struct Base2 { int i2{}; }; struct Derived : Base1, Base2 { int i3{}; }; std::shared_ptr<Derived> p(new Derived()); std::shared_ptr<Base2> q(p, static_cast<Base2*>(p.get())); std::cout << "q shares ownership with p, but points to Base2 subobject:\n" << "p.get(): " << p.get() << '\n' << "q.get(): " << q.get() << '\n' << "&(p->i1): " << &(p->i1) << '\n' << "&(p->i2): " << &(p->i2) << '\n' << "&(p->i3): " << &(p->i3) << '\n' << "&(q->i2): " << &(q->i2) << '\n'; }
Possible output:
Naked pointer: 42 in 0xacac20 Shared pointer: 42 in 0xacac50 Shared pointer with get(): 42 in 0xacac50 The shared_ptr's aliasing constructor demo. q shares ownership with p, but points to Base2 subobject: p.get(): 0xacac20 q.get(): 0xacac24 &(p->i1): 0xacac20 &(p->i2): 0xacac24 &(p->i3): 0xacac28 &(q->i2): 0xacac24
[edit] See also
dereferences the stored pointer (public member function) |