Difference between revisions of "cpp/numeric/complex/conj"
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(Use letters to mark the additional overloads in order to differentiate them from the real overloads.) |
Andreas Krug (Talk | contribs) m (<double> z(1, 2) -> <double> z(1.0, 2.0)) |
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int main() | int main() | ||
{ | { | ||
| − | std::complex<double> z(1, 2); | + | std::complex<double> z(1.0, 2.0); |
std::cout << "The conjugate of " << z << " is " << std::conj(z) << '\n' | std::cout << "The conjugate of " << z << " is " << std::conj(z) << '\n' | ||
<< "Their product is " << z * std::conj(z) << '\n'; | << "Their product is " << z * std::conj(z) << '\n'; | ||
Latest revision as of 09:20, 21 April 2023
| Defined in header <complex>
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| (1) | ||
template< class T > std::complex<T> conj( const std::complex<T>& z ); |
(until C++20) | |
| template< class T > constexpr std::complex<T> conj( const std::complex<T>& z ); |
(since C++20) | |
| Additional overloads (since C++11) |
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| Defined in header <complex>
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||
| (A) | ||
std::complex<float> conj( float f ); std::complex<double> conj( double f ); |
(until C++20) | |
| constexpr std::complex<float> conj( float f ); constexpr std::complex<double> conj( double f ); |
(since C++20) (until C++23) |
|
| template< class FloatingPoint > constexpr std::complex<FloatingPoint> conj( FloatingPoint f ); |
(since C++23) | |
| (B) | ||
template< class Integer > constexpr std::complex<double> conj( Integer i ); |
(until C++20) | |
| template< class Integer > constexpr std::complex<double> conj( Integer i ); |
(since C++20) | |
|
A,B) Additional overloads are provided for all integer and floating-point types, which are treated as complex numbers with zero imaginary component.
|
(since C++11) |
Contents |
[edit] Parameters
| z | - | complex value |
| f | - | floating-point value |
| i | - | integer value |
[edit] Return value
1) The complex conjugate of z.
A) std::complex(f).
B) std::complex<double>(i).
[edit] Notes
The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:
- If num has a standard(until C++23) floating-point type
T, then std::conj(num) has the same effect as std::conj(std::complex<T>(num)). - Otherwise, if num has an integer type, then std::conj(num) has the same effect as std::conj(std::complex<double>(num)).
[edit] Example
Run this code
#include <complex> #include <iostream> int main() { std::complex<double> z(1.0, 2.0); std::cout << "The conjugate of " << z << " is " << std::conj(z) << '\n' << "Their product is " << z * std::conj(z) << '\n'; }
Output:
The conjugate of (1,2) is (1,-2) Their product is (5,0)
[edit] See also
| returns the magnitude of a complex number (function template) | |
| returns the squared magnitude (function template) | |
| constructs a complex number from magnitude and phase angle (function template) | |
| C documentation for conj
| |
