Extending the namespace std
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[edit] Adding declarations to std
It is undefined behavior to add declarations or definitions to namespace std
or to any namespace nested within std
, with a few exceptions noted below.
#include <utility> namespace std { // a function definition added to namespace std: undefined behavior pair<int, int> operator+(pair<int, int> a, pair<int, int> b) { return {a.first + b.first, a.second + b.second}; } }
[edit] Adding template specializations
[edit] Class templates
It is allowed to add template specializations for any standard library class template to the namespace std
only if the declaration depends on at least one program-defined type and the specialization satisfies all requirements for the original template, except where such specializations are prohibited.
// Get the declaration of the primary std::hash template. // We are not permitted to declare it ourselves. // <typeindex> is guaranteed to provide such a declaration, // and is much cheaper to include than <functional>. #include <typeindex> // Specialize std::hash so that MyType can be used as a key in // std::unordered_set and std::unordered_map. Opening namespace // std can accidentally introduce undefined behavior, and is not // necessary for specializing class templates. template<> struct std::hash<MyType> { std::size_t operator()(const MyType& t) const { return t.hash(); } };
- Specializing the template std::complex for any type other than float, double, and long double is unspecified.
- Specializations of std::numeric_limits must define all members declared static const(until C++11)static constexpr(since C++11) in the primary template, in such a way that they are usable as integral constant expressions.
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(since C++11) |
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(until C++17) |
It is undefined behavior to declare a full or partial specialization of any member class template of a standard library class or class template.
This section is incomplete Reason: mini-example |
[edit] Function templates and member functions of templates
It is allowed to add template specializations for any standard library function template to the namespace |
(until C++20) |
It is undefined behavior to declare a full specialization of any standard library function template. |
(since C++20) |
This section is incomplete Reason: mini-example |
It is undefined behavior to declare a full specialization of any member function of a standard library class template:
This section is incomplete Reason: mini-example |
It is undefined behavior to declare a full specialization of any member function template of a standard library class or class template:
This section is incomplete Reason: mini-example |
[edit] Variable templates
It is undefined behavior to declare a full or partial specialization of any standard library variable template, except where explicitly allowed.
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(since C++14) |
[edit] Explicit instantiation of templates
It is allowed to explicitly instantiate a class (since C++20)template defined in the standard library only if the declaration depends on the name of at least one program-defined type and the instantiation meets the standard library requirements for the original template.
This section is incomplete Reason: mini-example |
[edit] Other restrictions
The namespace std
may not be declared as an inline namespace.
Addressing restrictionThe behavior of a C++ program is unspecified (possibly ill-formed) if it explicitly or implicitly attempts to form a pointer, reference (for free functions and static member functions) or pointer-to-member (for non-static member functions) to a standard library function or an instantiation of a standard library function template, unless it is designated an addressable function (see below). Following code was well-defined in C++17, but leads to unspecified behaviors and possibly fails to compile since C++20: #include <cmath> #include <memory> int main() { // by unary operator& auto fptr0 = &static_cast<float(&)(float, float)>(std::betaf); // by std::addressof auto fptr1 = std::addressof(static_cast<float(&)(float, float)>(std::betaf)); // by function-to-pointer implicit conversion auto fptr2 = static_cast<float(&)(float)>(std::riemann_zetaf); // forming a reference auto& fref = static_cast<float(&)(float)>(std::riemann_zetaf); } Designated addressable functions
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(since C++20) |
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
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LWG 120 | C++98 | users could explicitly instantiate standard library templates for non-user defined types |
prohibited |
LWG 232 | C++98 | users could explicitly specialize standard library templates if the declaration depends on a user-defined name of external linkage (which can refer to a non-user-defined type) |
only allowed for user-defined types |
LWG 422 | C++98 | users could specialize individual members or member templates without specializing the whole standard library class or class template |
the behavior is undefined in this case |