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std::reverse

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Revision as of 09:55, 25 May 2019 by Mgkrupa (Talk | contribs)

 
 
Algorithm library
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Defined in header <algorithm>
(1)
template< class BidirIt >
void reverse( BidirIt first, BidirIt last );
(until C++20)
template< class BidirIt >
constexpr void reverse( BidirIt first, BidirIt last );
(since C++20)
template< class ExecutionPolicy, class BidirIt >
void reverse( ExecutionPolicy&& policy, BidirIt first, BidirIt last );
(2) (since C++17)
1) Reverses the order of the elements in the range [first, last)
Behaves as if applying std::iter_swap to every pair of iterators first+i, (last-i) - 1 for each non-negative i < (last-first)/2
2) Same as (1), but executed according to policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true

Contents

Parameters

first, last - the range of elements to reverse
policy - the execution policy to use. See execution policy for details.
Type requirements
-
BidirIt must meet the requirements of ValueSwappable and LegacyBidirectionalIterator.

Return value

(none)

Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

  • If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
  • If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

See also the implementations in libstdc++ and libc++.

template<class BidirIt>
void reverse(BidirIt first, BidirIt last)
{
    while ((first != last) && (first != --last)) {
        std::iter_swap(first++, last);
    }
}

Complexity

Exactly (last - first)/2 swaps.

Example

#include <vector>
#include <iostream>
#include <iterator>
#include <algorithm>
 
int main()
{
    std::vector<int> v{1,2,3};
    std::reverse(std::begin(v), std::end(v));
    for(auto e : v) std::cout << e;
    std::cout << '\n';
 
    int a[] = {4, 5, 6, 7};
    std::reverse(std::begin(a), std::end(a));
    for(auto e : a) std::cout << e;
}

Output:

321
7654


See also

creates a copy of a range that is reversed
(function template) [edit]