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std::merge

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Revision as of 05:09, 14 April 2020 by Ybab321 (Talk | contribs)

 
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merge
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Defined in header <algorithm>
(1)
template< class InputIt1, class InputIt2, class OutputIt >

OutputIt merge( InputIt1 first1, InputIt1 last1,
                InputIt2 first2, InputIt2 last2,

                OutputIt d_first );
 (until C++20)
template< class InputIt1, class InputIt2, class OutputIt >

constexpr OutputIt merge( InputIt1 first1, InputIt1 last1,
                          InputIt2 first2, InputIt2 last2,

                          OutputIt d_first );
 (since C++20)
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class ForwardIt3 >

ForwardIt3 merge( ExecutionPolicy&& policy,
                  ForwardIt1 first1, ForwardIt1 last1,
                  ForwardIt2 first2, ForwardIt2 last2,

                  ForwardIt3 d_first );
 (2) (since C++17)
(3)
template< class InputIt1, class InputIt2, class OutputIt, class Compare>

OutputIt merge( InputIt1 first1, InputIt1 last1,
                InputIt2 first2, InputIt2 last2,

                OutputIt d_first, Compare comp );
 (until C++20)
template< class InputIt1, class InputIt2, class OutputIt, class Compare>

constexpr OutputIt merge( InputIt1 first1, InputIt1 last1,
                          InputIt2 first2, InputIt2 last2,

                          OutputIt d_first, Compare comp );
 (since C++20)
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class ForwardIt3, class Compare>

ForwardIt3 merge( ExecutionPolicy&& policy,
                  ForwardIt1 first1, ForwardIt1 last1,
                  ForwardIt2 first2, ForwardIt2 last2,

                  ForwardIt3 d_first, Compare comp );
 (4) (since C++17)

Merges two sorted ranges [first1, last1) and [first2, last2) into one range [d_first, d_last), where d_last is d_first + (last1 - first1) + (last2 - first2), such that this range satisfies std::is_sorted(d_first, d_last) or std::is_sorted(d_first, d_last, comp), respectively.

A sequence is said to be sorted with respect to a comparator comp if for any iterator it pointing to the sequence and any non-negative integer n such that it + n is a valid iterator pointing to an element of the sequence, comp(*(it + n), *it) evaluates to false.

1) Elements are compared using operator<.
3) Elements are compared using the given binary comparison function comp.
2,4) Same as (1,3), but executed according to policy. These overloads participate in overload resolution only if

std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true.

(until C++20)

std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true.

(since C++20)

This merge function is stable, which means that for equivalent elements in the original two ranges, the elements from the first range (preserving their original order) precede the elements from the second range (preserving their original order).

The behavior is undefined if the destination range overlaps either of the input ranges (the input ranges may overlap each other).

Contents

Parameters

first1, last1 - the first range of elements to merge
first2, last2 - the second range of elements to merge
d_first - the beginning of the destination range
policy - the execution policy to use. See execution policy for details.
comp - comparison function object (i.e. an object that satisfies the requirements of Compare) which returns ​true if the first argument is less than (i.e. is ordered before) the second.

The signature of the comparison function should be equivalent to the following:

bool cmp(const Type1& a, const Type2& b);

While the signature does not need to have const&, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1& is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2. ​

Type requirements
-
InputIt1, InputIt2 must meet the requirements of LegacyInputIterator.
-
ForwardIt1, ForwardIt2, ForwardIt3 must meet the requirements of LegacyForwardIterator.
-
OutputIt must meet the requirements of LegacyOutputIterator.

Return value

An output iterator to element past the last element copied.

Complexity

1,3) At most std::distance(first1, last1) + std::distance(first2, last2) - 1 comparisons.
2,4) O(std::distance(first1, last1) + std::distance(first2, last2))

Exceptions

The overloads with a template parameter named ExecutionPolicy report errors as follows:

  • If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
  • If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Notes

This algorithm performs a similar task as std::set_union does. Both consume two sorted input ranges and produce a sorted output with elements from both inputs. The difference between these two algorithms is with handling values from both input ranges which compare equivalent (see notes on LessThanComparable). If any equivalent values appeared n times in the first range and m times in the second, std::merge would output all n+m occurrences whereas std::set_union would output std::max(n, m) ones only. So std::merge outputs exactly std::distance(first1, last1) + std::distance(first2, last2) values and std::set_union may produce fewer.

Possible implementation

See also the implementations in libstdc++ and libc++.


First version 
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt merge(InputIt1 first1, InputIt1 last1,
               InputIt2 first2, InputIt2 last2,
               OutputIt d_first)
{
    for (; first1 != last1; ++d_first) {
        if (first2 == last2) {
            return std::copy(first1, last1, d_first);
        }
        if (*first2 < *first1) {
            *d_first = *first2;
            ++first2;
        } else {
            *d_first = *first1;
            ++first1;
        }
    }
    return std::copy(first2, last2, d_first);
}
Second version 
template<class InputIt1, class InputIt2,
         class OutputIt, class Compare>
OutputIt merge(InputIt1 first1, InputIt1 last1,
               InputIt2 first2, InputIt2 last2,
               OutputIt d_first, Compare comp)
{
    for (; first1 != last1; ++d_first) {
        if (first2 == last2) {
            return std::copy(first1, last1, d_first);
        }
        if (comp(*first2, *first1)) {
            *d_first = *first2;
            ++first2;
        } else {
            *d_first = *first1;
            ++first1;
        }
    }
    return std::copy(first2, last2, d_first);
}

Example

Run this code
#include <iostream>
#include <iterator>
#include <algorithm>
#include <vector>
#include <random>
#include <functional>
 
int main()
{
    // fill the vectors with random numbers
    std::random_device rd;
    std::mt19937 mt(rd());
    std::uniform_int_distribution<> dis(0, 9);
 
    std::vector<int> v1(10), v2(10);
    std::generate(v1.begin(), v1.end(), std::bind(dis, std::ref(mt)));
    std::generate(v2.begin(), v2.end(), std::bind(dis, std::ref(mt)));
 
    // sort
    std::sort(v1.begin(), v1.end());
    std::sort(v2.begin(), v2.end());
 
    // output v1
    std::cout << "v1 : ";
    std::copy(v1.begin(), v1.end(), std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
 
    // output v2
    std::cout << "v2 : ";
    std::copy(v2.begin(), v2.end(), std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
 
    // merge
    std::vector<int> dst;
    std::merge(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(dst));
 
    // output
    std::cout << "dst: ";
    std::copy(dst.begin(), dst.end(), std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
}

Possible output: 

v1 : 0 1 3 4 4 5 5 8 8 9 
v2 : 0 2 2 3 6 6 8 8 8 9 
dst: 0 0 1 2 2 3 3 4 4 5 5 6 6 8 8 8 8 8 9 9

See also

 merges two ordered ranges in-place
(function template) [edit]
(C++11)
 checks whether a range is sorted into ascending order
(function template) [edit]
computes the union of two sets
(function template) [edit]
sorts a range into ascending order
(function template) [edit]
sorts a range of elements while preserving order between equal elements
(function template) [edit]
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