std::swap_ranges
From cppreference.com
Defined in header <algorithm>
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(1) | ||
template< class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, |
(until C++20) | |
template< class ForwardIt1, class ForwardIt2 > constexpr ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ExecutionPolicy&& policy, |
(2) | (since C++17) |
1) Exchanges elements between range
[first1, last1)
and another range starting at first2
. Precondition: the two ranges
[first1, last1)
and [first2, last2)
do not overlap, where last2 = std::next(first2, std::distance(first1, last1)).2) Same as (1), but executed according to
policy
. This overload participates in overload resolution only if
std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. |
(until C++20) |
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. |
(since C++20) |
Contents |
Parameters
first1, last1 | - | the first range of elements to swap |
first2 | - | beginning of the second range of elements to swap |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator.
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-The types of dereferenced ForwardIt1 and ForwardIt2 must meet the requirements of Swappable
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Return value
Iterator to the element past the last element exchanged in the range beginning with first2
.
Complexity
linear in the distance between first1
and last1
.
Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
template<class ForwardIt1, class ForwardIt2> constexpr ForwardIt2 swap_ranges(ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2) { while (first1 != last1) { std::iter_swap(first1++, first2++); } return first2; } |
Example
Demonstrates swapping of subranges from different containers.
Run this code
#include <list> #include <vector> #include <iostream> #include <algorithm> auto print = [](auto comment, auto const& seq) { std::cout << comment; for (const auto& e : seq) { std::cout << e << ' '; } std::cout << '\n'; }; int main() { std::vector<char> v = {'a', 'b', 'c', 'd', 'e'}; std::list<char> l = {'1', '2', '3', '4', '5'}; print("Before swap_ranges:\n" "v: ", v); print("l: ", l); std::swap_ranges(v.begin(), v.begin()+3, l.begin()); print("After swap_ranges:\n" "v: ", v); print("l: ", l); }
Output:
Before swap_ranges: v: a b c d e l: 1 2 3 4 5 After swap_ranges: v: 1 2 3 d e l: a b c 4 5
See also
swaps the elements pointed to by two iterators (function template) | |
swaps the values of two objects (function template) | |
(C++20) |
swaps two ranges of elements (niebloid) |