std::swap_ranges
From cppreference.com
Defined in header <algorithm>
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template< class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2 ); |
(1) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ExecutionPolicy&& policy, ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2 ); |
(2) | (since C++17) |
1) Exchanges elements between range
[first1, last1)
and another range starting at first2
. 2) Same as (1), but executed according to
policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueContents |
Parameters
first1, last1 | - | the first range of elements to swap |
first2 | - | beginning of the second range of elements to swap |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-The types of dereferenced ForwardIt1 and ForwardIt2 must meet the requirements of Template:concept
|
Return value
Iterator to the element past the last element exchanged in the range beginning with first2
.
Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
template<class ForwardIt1, class ForwardIt2> ForwardIt2 swap_ranges(ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2) { while (first1 != last1) { std::iter_swap(first1++, first2++); } return first2; } |
Example
Demonstrates swapping of subranges from different containers
Run this code
#include <algorithm> #include <list> #include <vector> #include <iostream> int main() { std::vector<int> v = {1, 2, 3, 4, 5}; std::list<int> l = {-1, -2, -3, -4, -5}; std::swap_ranges(v.begin(), v.begin()+3, l.begin()); for(int n : v) std::cout << n << ' '; std::cout << '\n'; for(int n : l) std::cout << n << ' '; std::cout << '\n'; }
Output:
-1 -2 -3 4 5 1 2 3 -4 -5
Complexity
linear in the distance between first
and last
See also
swaps the elements pointed to by two iterators (function template) | |
swaps the values of two objects (function template) |